使用 zxing 编码和解码随机字节数组 [英] Encoding and decoding random byte array with zxing
问题描述
我正在尝试使用二维码传输字节数组，因此为了测试，我决定生成一个随机字节数组，将其编码为二维码，然后对其进行解码.我使用 ISO-8859-1 将字节数组转换为字符串 s.t 它在传输时不会丢失数据:
I'm trying to transfer a byte array with QR code, so for testing, I decided to generate a random byte array, encode it as QR code, then decode it. I used ISO-8859-1 to convert byte array to string s.t it does not lose data while transmission:
对于编码器端:
byte []buffer = new byte[11];
com.google.zxing.Writer writer = new QRCodeWriter();
Random randomGenerator = new Random();
for(int i=0;i<=10;i++){
buffer[i]=(byte) randomGenerator.nextInt(254);
}
// Log.i("time1","original: "+Arrays.toString(buffer));
String decoded = null;
try {
decoded = new String(buffer, "ISO-8859-1");
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
result=writer.encode(decoded, BarcodeFormat.QR_CODE, 500, 500);
} catch (WriterException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
这样我就将字节数组转换为二维码了，没有问题.但对于接收方:
In this way I have converted byte array to QR code, it has no problem. But for the receiver side:
LuminanceSource source = new PlanarYUVLuminanceSource(data,640,480,0,0,640,480,false);
bmtobedecoded = new BinaryBitmap(new HybridBinarizer(source));
Map<DecodeHintType,Object> mp=new HashMap<DecodeHintType, Object>();
mp.put(DecodeHintType.TRY_HARDER, true);
try {
result= qrr.decode(bmtobedecoded,mp);
} catch (NotFoundException e) {
Log.i("123","not found");
e.printStackTrace();
} catch (ChecksumException e) {
Log.i("123","checksum");
e.printStackTrace();
} catch (FormatException e) {
Log.i("123","format");
e.printStackTrace();
}
我试图解码生成的二维码，但它抛出了 NotFoundException.有人可以帮我解决这个问题吗?
I tried to decode the generated QR code, but it throws out NotFoundException. Can someone help me with this issue?
更新 1:我确认解码器与普通二维码完美配合，我还添加了 DecodeHintType.try_harder 但仍然不行.
Update 1: I confirmed that the decoder works perfectly with the normal QR, I also added DecodeHintType.try_harder but still no good.
更新 2:澄清一下，以下是我在字节数组和字符串之间进行转换的操作:
Update 2: To clarify, below is what I did to convert between byte array and string:
Random randomGenerator = new Random();
for(int i=0;i<=10;i++){
buffer[i]=(byte) randomGenerator.nextInt(254);
}
Log.i("time1","original: "+Arrays.toString(buffer));
String decoded = null;
try {
decoded = new String(buffer, "ISO-8859-1");
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Log.i("time1","encoded string:" + decoded);
BitMatrix result=null;
try {
result=qw.encode(decoded, BarcodeFormat.QR_CODE, 500, 500);
} catch (WriterException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
iv.setImageBitmap(encodematrix(result));
byte[] encoded = null;
try {
encoded = decoded.getBytes("ISO-8859-1");
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Log.i("time1","result byte array:" + java.util.Arrays.toString(encoded));
如果你运行这个，你可以很容易地看到你最终可以得到完全相同的数组.我对此没有任何问题.
If you run this, you can easily see that you can get exactly the same array in the end. I have no problem with this.
更新 3:我也尝试使用 UTF-8 对其进行编码，但会丢失数据，因此无法在编码器中使用.
Update 3: I also tried encoding it using UTF-8, but it loses data, so it cannot be the used in encoder.
更新 4:刚刚添加:
Map<DecodeHintType,Object> mp=new HashMap<DecodeHintType, Object>();
mp.put(DecodeHintType.CHARACTER_SET, "ISO-8859-1");
在解码器中，仍然抛出异常.
in the decoder, still throwing out exception.
推荐答案
尝试 PURE_BARCODE 模式作为检测提示.奇怪的是，当图像只是纯合成图像时，发现者模式的误报检测是一个更大的问题.启发式假设一张照片，它没有这些问题.在这种替代模式下，它可以利用知道它是纯图像而不是照片的优势，并且速度更快并且永远不会出错.
Try PURE_BARCODE mode as a detection hint. Strangely, false positive detection of finder patterns is a much bigger problem when the image is just a pure synthetic image. The heuristics assume a photo, which doesn't have these problems. In this alternate mode it can take advantage of knowing it's a pure image and not a photo and be much faster and never get the detection wrong.
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