从父子 JSON 数据中获取所有子项 [英] Get all children from parent child JSON data

问题描述

我有父子 JSON 数据，我想从选定的父项中获取所有子项(嵌套子项).

I have parent-child JSON data and I want get all children (nested children) from selected parent.

例如，我有 JSON 数据:

For example, I have JSON data :

[{
  "id": 1,
  "parent": 0,
  "name": "Parent"
}, {
  "id": 2,
  "parent": 1,
  "name": "Child 1"
}, {
  "id": 3,
  "parent": 2,
  "name": "Grand Child 1"
}, {
  "id": 4,
  "parent": 2,
  "name": "Grand Child 2"
}, {
  "id": 5,
  "parent": 1,
  "name": "Child 2"
}]

我有函数 findAllChildren(1)，其中1"是父"，然后函数的结果应该是:

And I have function findAllChildren(1), where "1" is "parent" and then result of function should be :

[{
  "id": 2,
  "parent": 1,
  "name": "Child 1"
}, {
  "id": 3,
  "parent": 2,
  "name": "Grand Child 1"
}, {
  "id": 4,
  "parent": 2,
  "name": "Grand Child 2"
}, {
  "id": 5,
  "parent": 1,
  "name": "Child 2"
}]

在其他情况下，如果我调用 findAllChildren(2)，函数的结果应该如下所示:

And in other case, if i call findAllChildren(2), result of the function should like below :

[{
  "id": 3,
  "parent": 2,
  "name": "Grand Child 1"
}, {
  "id": 4,
  "parent": 2,
  "name": "Grand Child 2"
}]

创建函数来解决这种情况的正确方法是什么?谢谢.

What is the proper way to create function to solve that case? Thank you.

推荐答案

您可以遍历原始数据并查找具有指定 id 为 parent_id 的项目.如果找到，则对元素的 id 递归执行相同操作.

You can just iterate over the original data and look for items that has the specified id as parent_id. If found, do the same recursively with the element's id.

在这里查看:https://jsfiddle.net/6ydog1tj/2/>

function findAllChildren (id, results, depth) {
    for (d in data) {
        if (data[d].parent == id) {
            data[d].depth = depth
            results.push(data[d])
            findAllChildren(data[d].id, results, depth + 1)
        }
    }
}

var results = []
findAllChildren(1, results, 0)

$('body').append(results.map(function (element) { return Array(element.depth + 1).join(' -> ') + element.name + '<br>' }))

console.log(results)

打印出来

Child 1
-> Grand Child 1
-> Grand Child 2
Child 2

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