我如何从 R 中的聚合函数解释这个错误 [英] How do I interpret this error from aggregate function in R

问题描述

我需要一些有关聚合函数的帮助.这是我的数据:(它显示了三列，但我的理解是有两列，分别命名为 V1 和 V3.显示从 330 开始的数字的第一列是 row.names.)

I need some help with the aggregate function. Here is my data: (it shows three columns however my understanding is that there is 2 columns, named V1 and V3 respectively. The first column showing numbers starting at 330 are the row.names.)

我想在 V3 上使用 V1 作为键做一个简单的聚合函数，比如 mean.我感觉我的数据类型不正确，但我不知道如何转换！

I'd like to do a simple aggregate function like mean on V3 using V1 as the key. I have a feeling my data type is not correct, but I don't know how to convert!

> testing
                        V1                 V3
330 chr1_10440000_11000000   1.59987556934357
335 chr1_10440000_11000000    89.185531616211
338 chr1_10440000_11000000   1.25018584728241
340 chr1_10440000_11000000   5.91385841369629
342 chr1_10440000_11000000   1.68633282184601
345 chr1_11000000_11240000  0.118176721036434
349 chr1_11000000_11240000     9.131010055542
350 chr1_11000000_11240000 0.0575727485120296
352 chr1_11000000_11240000   11.7410087585449
353 chr1_11000000_11240000   10.5057544708252
356 chr1_11000000_11240000   2.35379362106323
360 chr1_11240000_12040000   0.08041662722826
363 chr1_11240000_12040000   1.62903010845184
366 chr1_11240000_12040000  0.039043802767992
368 chr1_11240000_12040000   1.90981948375702
369 chr1_11240000_12040000   7.19360542297363
370 chr1_11240000_12040000   5.95961284637451
371 chr1_11240000_12040000   4.40743684768677
372 chr1_11240000_12040000  0.600234627723694
373 chr1_11240000_12040000   20.9832191467285
> 

这是我尝试使用的代码和相应的错误/警告消息:

Here is the code I am trying to use and the corresponding error/warning message:

> aggregate(testing, by=list(testing$V1), FUN=mean )
                 Group.1 V1 V3
1 chr1_10440000_11000000 NA NA
2 chr1_11000000_11240000 NA NA
3 chr1_11240000_12040000 NA NA
Warning messages:
1: In mean.default(X[[1L]], ...) :
  argument is not numeric or logical: returning NA
2: In mean.default(X[[2L]], ...) :
  argument is not numeric or logical: returning NA
3: In mean.default(X[[3L]], ...) :
  argument is not numeric or logical: returning NA
4: In mean.default(X[[1L]], ...) :
  argument is not numeric or logical: returning NA
5: In mean.default(X[[2L]], ...) :
  argument is not numeric or logical: returning NA
6: In mean.default(X[[3L]], ...) :
  argument is not numeric or logical: returning NA
> 

推荐答案

aggregate(V3 ~ V1, testing, FUN = function(x) mean(as.numeric(as.character(x))))

应该可以解决问题.在应用函数之前，变量被转换为数字变量.

should do the trick. The variable is transformed to a numeric one before applying the function.

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