Angular 2 - 基于 JSON 响应的切换按钮 [英] Angular 2 - Toggle button based on JSON response

问题描述

我们如何根据 Angular 2 中的 JSON 响应将按钮切换为是/否?

解决方案

使用以下代码切换按钮

import {Component, NgModule, VERSION} from '@angular/core'从@angular/platform-b​​rowser"导入 {BrowserModule}@成分({选择器:'我的应用'，模板:`<div><button *ngIf='toggleButton' (click)='toggleButton = false'>按钮一</button><button *ngIf='!toggleButton' (click)='toggleButton = true'>按钮二</button>

`，})出口类应用{名称:字符串；切换按钮:布尔值:真；//切换按钮的标志在单击按钮时切换其值构造函数(){this.name = `角度！v${VERSION.full}`}}@NgModule({进口:[浏览器模块]，声明:[应用程序]，引导程序:[应用程序]})导出类 AppModule {}

How can we toggle a button to Yes/No based on JSON response in angular 2?

解决方案

Use following code to toggle button

import {Component, NgModule, VERSION} from '@angular/core'
import {BrowserModule} from '@angular/platform-browser'

@Component({
  selector: 'my-app',
  template: `
    <div>
      <button *ngIf='toggleButton' (click)='toggleButton = false'>Button One</button>
      <button *ngIf='!toggleButton' (click)='toggleButton = true'>Button Two</button>
    </div>
  `,
})
export class App {
  name:string;
  toggleButton: boolean: true; // Flag to toggle your button toggling its value on click of button
  constructor() {
    this.name = `Angular! v${VERSION.full}`
  }
}

@NgModule({
  imports: [ BrowserModule ],
  declarations: [ App ],
  bootstrap: [ App ]
})
export class AppModule {}

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