如何使用 ng-style 设置 div 的背景图像 [英] How to Set Background image of div with ng-style

问题描述

基本上我有一个链接，当它被点击时，我会显示一个模式.现在我可以在模态上显示其他属性，如标题，除了背景图像！呃呃！

这是模态:

<div id="modalHeader"><div style="padding-top: 10px;">{{selectedMeal.title}}</div>

这些是链接:

<div ng-click='selectMeal(meal)' class="contentItem" ng-repeat='meal in recipes |filter:searchText' ng-style="{'background-image':'url({{meal.url }})'}"><span id="contentItemHeader">{{meal.title }}</span><span id="contentItemLevel">{{meal.level }}</span>

json:

食谱:[{"type": "早餐","title": "辣椒酱","description": "一种香辣香辣的辣椒，搭配碎牛肉、芸豆、西红柿、洋葱和大蒜.最好搭配米饭配上一团酸奶油和一些奶酪.",评分":4，持续时间":12，"level":"中等","url":"http://31.media.tumblr.com/bc0ea7c5f95701bff499f78b59d23e68/tumblr_mr74z9Lt3O1rs0z5go1_500.jpg",配料":[{蔬菜":40ml"}],方法":[{1":在一个中等大小的汤锅中，将油加热.炒洋葱、辣椒和大蒜直至变软."}]},{"type": "早餐","title": "辣面","description": "一种香辣香辣的辣椒，搭配碎牛肉、芸豆、西红柿、洋葱和大蒜.最好搭配米饭配上一团酸奶油和一些奶酪.",评分":5，持续时间":30，"level":"热","url":"http://38.media.tumblr.com/875b5eeb5b1efa37d2e9d36fbad836d3/tumblr_mzczesVrZD1rimr6yo1_1280.jpg",配料":[{蔬菜":40ml"}],方法":[{1":在一个大小合适的汤锅中，将油加热.炒洋葱、辣椒和大蒜直至变软."}]}]

解决方案

您在使用单引号时犯了一些错误，您必须将变量放在单引号之外.

对于这个 div

这部分被视为字符串

'url({{selectedMeal.url}})'

而您希望 angular 解析此变量

{{selectedMeal.url}}

所以要解决这个问题，正确的语法是

Basically i have a link, and when it's clicked, i display a modal. Now i can display other properties on the modal like title except the background Image ! urghhh !

This is the modal:

<div class="modalContainer" ng-style="{'background-image':'url({{selectedMeal.url}})'}">

                <div id="modalHeader"> 
                <div style="padding-top: 10px;">{{selectedMeal.title}}</div>

                </div>
</div>

These are the links:

<div ng-click='selectMeal(meal)' class="contentItem" ng-repeat='meal in recipes | filter:searchText' ng-style="{'background-image':'url({{ meal.url }})'}">
                    <span id="contentItemHeader">{{ meal.title }}</span>
                    <span id="contentItemLevel">{{ meal.level }}</span>
</div>

json:

recipes:[
    {
      "type": "Breakfast",
      "title": "Chili con carne",
      "description": "A spicy and fragrant chili with ground beef, kidney beans, tomatoes, onions and garlic. Best served over rice with a dollop of sour cream and some cheese on top.",
      "ratings": 4,
      "duration": 12,
      "level":"medium",
      "url":"http://31.media.tumblr.com/bc0ea7c5f95701bff499f78b59d23e68/tumblr_mr74z9Lt3O1rs0z5go1_500.jpg",
      "ingredients": 
          [
            {
              "vegetable": "40ml"
            }
          ],
      "method": 
          [
            {
              "1": "In a medium sized stock pot, heat the oil over  heat. Saute onions, chile peppers andgarlic until soft."
            }
          ]
    },

    {
      "type": "Breakfast",
      "title": "Spicy Noodle",
      "description": "A spicy and fragrant chili with ground beef, kidney beans, tomatoes, onions and garlic. Best served over rice with a dollop of sour cream and some cheese on top.",
      "ratings": 5,
      "duration": 30,
      "level":"hot",
      "url":"http://38.media.tumblr.com/875b5eeb5b1efa37d2e9d36fbad836d3/tumblr_mzczesVrZD1rimr6yo1_1280.jpg",
      "ingredients": 
          [
            {
              "vegetable": "40ml"
            }
          ],
      "method": 
          [
            {
              "1": "In a  sized stock pot, heat the oil over  heat. Saute onions, chile peppers andgarlic until soft."
            }
          ]
    }]

解决方案

You have made some mistakes using single quotes, you have to take your variable outside the single quotes.

For this div

<div class="modalContainer" ng-style="{'background-image':'url({{selectedMeal.url}})'}">

This part is being treated as a string

'url({{selectedMeal.url}})'

Whereas you would want angular to parse this variable

{{selectedMeal.url}}

So to solve this, the correct syntax is

<div class="modalContainer" 
  ng-style="{'background-image': 'url(' + selectedMeal.url + ')'}">

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