ng-repeat 指定起始索引 [英] ng-repeat specify a starting index

问题描述

如何指定 ng-repeat 指令将要开始的索引而不是零?

How can I specify an index where an ng-repeat directive is going to start instead of zero?

我有一组结果，我只需要指定与零不同的起始结果.

I have a set of results and I just need to specify the starting one, which is different from zero.

推荐答案

无需编写任何代码，Angular 已经通过 现有 内置的 limitTo 过滤器.只需使用负限制.来自 limit 参数的文档:

No need to code anything, angular has done this with the existing built-in limitTo filter. Just use a negative limit. From the docs for the limit argument:

返回的数组或字符串的长度.如果限制数是正，限制从源头开始的项目数数组/字符串被复制.如果数量为负数，限制数量复制源数组/字符串末尾的项目.限制如果超过 array.length 将被修剪.如果未定义限制，则输入将原样返回.

The length of the returned array or string. If the limit number is positive, limit number of items from the beginning of the source array/string are copied. If the number is negative, limit number of items from the end of the source array/string are copied. The limit will be trimmed if it exceeds array.length. If limit is undefined, the input will be returned unchanged.

所以你会像这样在模板中使用它:

So you would use it like so in the template:

<ul>
   <li data-ng-repeat="i in list | limitTo: (offset - list.length)">{{i}}</li>
</ul>

其中 offset 是您的起始索引.请参阅示例 plunker.

where offset is your start index. See sample plunker.

有一个可选的 begin 参数，因此您不需要使用负 limit 但 begin 在 angular v1 之前不可用.4 所以我在我的例子中坚持了一个负 limit.

There is an optional begin argument so you don't need use a negative limit but the begin was not available before angular v1.4 so I have stuck to a negative limit in my example.

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