使用空对象进行角度排序 [英] Angular Sorting with null objects

问题描述

当我按 ASC 排序时，我需要在顶部取空值的记录

I need to take records with null values on top , when I'm sorting by ASC

<tr ng-repeat="footballer in footballers=(footballers | orderBy:predicate)">
predicate : ['team.name','id]

有些足球运动员没有团队，所以团队object == null 和team.name==null，我需要让他们在顶部

Some footballers have no team, so team object == null and team.name==null, and I need to have them on the top

我想重写排序函数，但我需要保存谓词

I wanted to rewrite sort function, but I need to save predicate

推荐答案

你可以在你的控制器中使用这样的东西:

You can use something like this in your controller:

$scope.nullsToTop = function(obj) {
  return (angular.isDefined(obj.team) ? 0 : -1);
};

在 HTML 上:

<tr ng-repeat="footballer in footballers | orderBy:[nullsToTop].concat(predicate)">

这样你就可以单独维护你的谓词.只需在 orderBy 表达式中连接 nullsToTop 函数以先运行它.

This way you can maintain your predicate separately. Just concat the nullsToTop function in the orderBy expression to run it first.

Plunker

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