打破 Angularjs 中的承诺 [英] Break Out of then promises in Angularjs
问题描述
我试图找到一种方法来打破 AngularJS 代码中的承诺链.显而易见的方法是返回一个对象,然后检查链中每个then"函数的有效性.
I am trying to find a way to break out of a promise chain in AngularJS code. The obvious way was to return an object and then check is validity in every "then" function in the chain.
我想找到一种更优雅的方式来打破 then 链.
I would like to find a more elegant way of breaking out of a then chain.
推荐答案
在 angular 中,有 $q 服务可以注入指令、控制器等,这是 Kris Kowal 的 Q 的一个紧密实现.所以在 then 函数内部,而不是返回一个值或其他会链接到下一个thenable"函数的东西,只需返回一个 $q.reject('reject reason');
In angular, there is the $q service that can be injected in directives, controllers etc, that is a close implentation of Kris Kowal's Q.
So inside of then function instead of returning a value or something else that would be chained to the next "thenable" function, just return a $q.reject('reject reason');
示例:
angular.module('myQmodule',[])
.controller('exController',['$q',function($q){
//here we suppose that we have a promise-like function promiseFunction()
promiseFunction().then(function(result1){
//do the check we want in order to end chain
if (endChainCheck) {
return $q.reject('give a reason');
}
return;
})
.then(function(){
//this will never be entered if we return the rejected $q
})
.catch(function(error){
//this will be entered if we returned the rejected $q with error = 'give a reason'
});
}]);
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