将 formControlName 转发到 Angular 中的内部组件 [英] Forwarding formControlName to inner component in Angular
问题描述
我有一个自定义控件组件
,我将它包装到
.SomeInput 是封装的,有自己的 API 并支持响应式表单.ExtSomeInput 是作为 SomeInput 的高级包装器创建的.
I have one custom control component <some-input>
that i wrapped to <ext-some-input>
. SomeInput is encapsulated, has own API and supports reactive forms.
ExtSomeInput is created as high-level wrapper over SomeInput.
我有以下 html:
<form [formGroup]="form">
<ext-some-input formControlName="name">
</form>
和ExtSomeInput的html:
<some-input formControlName="_???_"></some-input>
问题是如何将 formControlName 转发到内部的 SomeInput 组件?我需要将表单和内部 formControl 联系起来.这可能吗?
The question is how to forward formControlName to inner SomeInput component? I need to tie the form and inner formControl up. Is this possible?
我用这个问题创建了 stackblitz 项目:这里
I've created stackblitz project with this issue: here
推荐答案
你的内部组件可以接受 @Input
controlName
但它不会开箱即用:
Your inner component can take @Input
controlName
but it won't work out of the box:
错误:formControlName 必须与父 formGroup 指令一起使用.
Error: formControlName must be used with a parent formGroup directive.
为了将您的控件与父 FormGroup 绑定,您可以定义 viewProvider
如下:
In order to tie your control with parent FormGroup you can define viewProvider
as follows:
import { Component, Input, OnInit} from '@angular/core';
...
import { ControlContainer, FormGroupDirective } from '@angular/forms';
@Component({
...
viewProviders: [
{
provide: ControlContainer,
useExisting: FormGroupDirective
}
]
})
export class DateWrapperComponent implements OnInit {
@Input() controlName: string;
}
如果您不知道哪个指令作为 ControlContainer
(FormGroupDirective
、FormGroupName
或 FormArrayName
code>) 您可以使用更通用的方法:
In case you don't know which exactly directive is provided as a ControlContainer
(FormGroupDirective
, FormGroupName
or FormArrayName
) you can use more generic approach:
viewProviders: [
{
provide: ControlContainer,
useFactory: (container: ControlContainer) => container,
deps: [[new SkipSelf(), ControlContainer]]
}
]
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