转换匿名函数的输入 [英] Convert input of an anonymous function

问题描述

我有一个匿名函数 A 带有两个参数.我需要转换这个函数，使其接受一个参数，将另一个参数更改为常量.

I have an anonymous function A taking two arguments. I need to convert this function so it takes one argument, by changing the other argument to a constant.

例如有一个函数:A = @(X, Y) X + Y;我现在想要:B = @(Y) 3 + Y;

For example having a function: A = @(X, Y) X + Y; I would like now to have: B = @(Y) 3 + Y;

这在数学上似乎是很正常的事情，所以我猜想在 MATLAB 中有一种方法可以做这样的事情.但是我找不到解决方案.

This seems to be a normal thing to do in mathematics, so I guess there is a way to do such thing in MATLAB. I cannot find the solution though.

我需要做这样的事情的原因是我有一个函数可以对A进行一些计算，但也需要解决A之一的问题的参数是常数.例如，为 X = 3 找到 A 的最小值.

The reason I need to do something like this is that I have a function that does some calculations on A, but also needs to solve problems when one of the A's arguments is constant. For example find a minimum of the A for X = 3.

推荐答案

您可以使用相同的匿名函数并将 X 作为 3 放入其中，但如果您想创建另一个匿名函数，方法如下:

You can use the same anonymous function and put X as 3 in it but if you want to create another anonymous function, here is how to do that:

A = @(X, Y) X + Y;   
B = @(Y) A(3,Y);     %Here you have put X=3

验证:

>> A(3,4)

ans =

     7

>> B(4)

ans =

     7

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