使用 Ant 就地过滤文件? [英] Filtering Files In-Place with Ant?

问题描述

我有一个文件目录，我想使用 Apache Ant(Linux 上的 1.7.1 版)对其进行就地"字符串过滤.

I have a directory of files for which I'd like to do "in-place" string filtering using Apache Ant (version 1.7.1 on Linux).

例如，假设在目录 mydir 中有文件 foo、bar 和 baz.进一步假设正则表达式 OLD([0-9]) 的所有出现都应该更改为 NEW\1，例如OLD2 →NEW2.(请注意，replace Ant 任务将不起作用，因为它不支持正则表达式过滤.)

For example, suppose that in directory mydir I have files foo, bar, and baz. Further suppose that all occurences of the regular expression OLD([0-9]) should be changed to NEW\1, e.g. OLD2 → NEW2. (Note that the replace Ant task won't work because it does not support regular expression filtering.)

这个测试场景可以用下面的 Bash 命令来创建(ant 会运行在当前目录，即 mydir 的父目录):

This test situation can be created with the following Bash commands (ant will be run in the current directory, i.e. mydir's parent directory):

mkdir mydir
for FILE in foo bar baz ; do echo "A OLD1 B OLD2 C OLD3" > mydir/${FILE} ; done

这是我第一次尝试用 Ant 进行过滤:

Here is my first attempt to do the filtering with Ant:

<?xml version="1.0"?>
<project name="filter" default="filter">
    <target name="filter">
        <move todir="mydir">
            <fileset dir="mydir"/>
            <filterchain>
                <tokenfilter>
                    <replaceregex pattern="OLD([0-9])" replace="NEW\1" flags="g"/>
                </tokenfilter>
            </filterchain>
        </move>
    </target>
</project>

运行第一个 Ant 脚本对 mydir 中的文件没有影响.overwrite 参数在 move Ant 任务中默认为 true.我什至摆弄了 granularity 设置，但这没有帮助.

Running this first Ant script has no effect on the files in mydir. The overwrite parameter is true by default with the move Ant task. I even fiddled with the granularity setting, but that didn't help.

这是我的第二次尝试，它有效"，但由于临时文件创建而有点烦人.此版本通过将内容移动到带有 filtered 后缀的文件来正确过滤内容，然后过滤后的内容会以原始文件名移回":

Here's my second attempt, which "works," but is slightly annoying because of temporary file creation. This version filters the content properly by moving the content to files with a filtered suffix, then the filtered content is "moved back" with original filenames:

<?xml version="1.0"?>
<project name="filter" default="filter">
    <target name="filter">
        <move todir="mydir">
            <globmapper from="*" to="*.filtered"/>
            <fileset dir="mydir"/>
            <filterchain>
                <tokenfilter>
                    <replaceregex pattern="OLD([0-9])" replace="NEW\1" flags="g"/>
                </tokenfilter>
            </filterchain>
        </move>
        <move todir="mydir">
            <globmapper from="*.filtered" to="*"/>
            <fileset dir="mydir"/>
        </move>
    </target>
</project>

第一次尝试(没有临时文件)可以工作吗?

推荐答案

参见 replace 任务:

<replace 
   dir="mydir" 
   includes="foo, bar, baz">
   <replacefilter token="OLD" value="NEW" />
</replace>

或replaceregexp 任务:

<replaceregexp
    file="${src}/build.properties"
    match="OldProperty=(.*)"
    replace="NewProperty=\1"
    byline="true"/>

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