基于Java中的元素属性将列表拆分为多个子列表 [英] Split a list into multiple sublist based on element properties in Java
问题描述
有没有办法将一个列表拆分为多个列表?.根据 it 元素的特定条件将列表分成两个或多个列表.
Is there a way to split a list to multiple list?. Given list into two or more list based on a particular condition of it elements.
final List<AnswerRow> answerRows= getAnswerRows(.........);
final AnswerCollection answerCollections = new AnswerCollection();
answerCollections.addAll(answerRows);
The AnswerRow has properties like rowId, collectionId
根据 collectionId 我想创建一个或多个 AnswerCollections
based on collectionId i want to create one or more AnswerCollections
推荐答案
如果您只想按 collectionId
对元素进行分组,您可以尝试类似
If you just want to group elements by collectionId
you could try something like
List<AnswerCollection> collections = answerRows.stream()
.collect(Collectors.groupingBy(x -> x.collectionId))
.entrySet().stream()
.map(e -> { AnswerCollection c = new AnswerCollection(); c.addAll(e.getValue()); return c; })
.collect(Collectors.toList());
以上代码将为每个 collectionId
生成一个 AnswerCollection
.
Above code will produce one AnswerCollection
per collectionId
.
使用 Java 6 和 Apache Commons Collections,以下代码产生与使用 Java 8 流的上述代码相同的结果:
With Java 6 and Apache Commons Collections, the following code produce the same results as the above code using Java 8 streams:
ListValuedMap<Long, AnswerRow> groups = new ArrayListValuedHashMap<Long, AnswerRow>();
for (AnswerRow row : answerRows)
groups.put(row.collectionId, row);
List<AnswerCollection> collections = new ArrayList<AnswerCollection>(groups.size());
for (Long collectionId : groups.keySet()) {
AnswerCollection c = new AnswerCollection();
c.addAll(groups.get(collectionId));
collections.add(c);
}
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