在 Adobe Air 中获取当前登录的操作系统用户 [英] Get the current logged in OS user in Adobe Air
问题描述
我需要 Air/Flex 应用程序中当前登录用户的名称.该应用程序将仅部署在 Windows 机器上.我想我可以通过对用户目录进行正则表达式来实现这一点,但我对其他方式持开放态度.
I need the name of the current logged in user in my Air/Flex application. The application will only be deployed on Windows machines. I think I could attain this by regexing the User directory, but am open to other ways.
推荐答案
您可以进行一些小的清理...
There's a couple of small cleanups you can make...
package
{
import flash.filesystem.File;
public class UserUtil
{
public static function get currentOSUser():String
{
var userDir:String = File.userDirectory.nativePath;
var userName:String = userDir.substr(userDir.lastIndexOf(File.separator) + 1);
return userName;
}
}
}
正如 Kevin 建议的,使用 File.separator
使目录拆分跨平台(刚刚在 Windows 和 Mac OS X 上测试).
As Kevin suggested, use File.separator
to make the directory splitting cross-platform (just tested on Windows and Mac OS X).
除非您正在寻找孩子,否则您不需要使用 resolvePath("")
.
You don't need to use resolvePath("")
unless you're looking for a child.
此外,使函数成为适当的 getter 允许绑定而无需任何进一步工作.
Also, making the function a proper getter allows binding without any further work.
在上面的例子中,我把它放到了一个UserUtil
类中,现在我可以绑定到UserUtil.currentOSUser
,例如:
In the above example I put it into a UserUtil
class, now I can bind to UserUtil.currentOSUser
, e.g:
<?xml version="1.0" encoding="utf-8"?>
<mx:WindowedApplication xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute">
<mx:Label text="{UserUtil.currentOSUser}"/>
</mx:WindowedApplication>
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