因为它正由另一个进程使用的FileStream无法访问该文件 [英] FileStream can't access the file because it's being used by another process

问题描述

我在ASP.NET Web应用程序新我碰到这个问题来了。

我有一个页面磨片有下载template.xls是pviously存储在SharePoint页面$ P $的按钮。我有下载方法，它的工作就好了。有问题的模板被保存在那里它应该是，在我的web应用程序的位置，在我的本地IIS文件夹上。
问题是要打开这个文件给最终用户。我需要一个弹出显示给用户，这样他就可以打开/保存该template.xls
我使用的是以下内容：

  //在我的本地IIS所在的文件所在的下载后路径
字符串_strFolderApp =〜/ ARQ /;
字符串_strFullFolderApp = _strFolderApp + _strFileName;
字符串apPath = System.Web.Hosting.HostingEnvironment.MapPath（_strFullFolderApp）;的FileStream _FileStream =新的FileStream（apPath，FileMode.Create，FileAccess.ReadWrite，FileShare.ReadWrite）;
//将字节块使用从字节数组数据此流。
_FileStream.Write（_contentFile，0，_contentFile.Length）;//打开文件
Response.Clear（）;
Response.AddHeader（内容处置，附件;文件名=+ _strFileName）;
Response.ContentType =;
Response.TransmitFile（apPath）;
Response.Flush（）;
File.Delete（apPath）;
到Response.End（）;
＃endregion//关闭文件流
_FileStream.Close（）;
 

我在网上搜索，所有的答案用FileShare.ReadWrite所以这两个过程将正常结束。但它不是为我工作，因为当code到达 Response.TransmitFile（apPath）; 我得到一个异常弹出，并没有显示。
例外：

的进程无法访问文件。'C：\\的Inetpub \\ wwwroot的\\ MyWebApp \\文件\\ TemplateSharePoint.xlsx'，因为它正被另一个进程使用的

请任何帮助将是AP preciated：）

修改
的 code更新的

 如果（_flgSPSDownload）
        {
            System.IO.FileStream _FileStream =新System.IO.FileStream（apPath，System.IO.FileMode.Create，System.IO.FileAccess.Write）;
            _FileStream.Write（_contentFile，0，_contentFile.Length）;
            _FileStream.Close（）;
            Response.Clear（）;
            Response.AddHeader（内容处置，附件;文件名=+ _strFileName）;
            //设置适当的ContentType。
            Response.ContentType =应用程序/ x-msexcel的;
            Response.TransmitFile（apPath）;
            Response.Flush（）;
            //直接将文件写入HTTP内容输出流。
            Response.WriteFile（apPath）;
            //File.Delete(apPath）;            //Process.Start(_strDestinationPath +//+ _strFileName）;
 

解决方案

据我所知，你在打开文件流，然后尝试再次打开它，关闭它之前。

该文件的初始开：

 的FileStream _FileStream =新的FileStream（apPath，FileMode.Create，FileAccess.ReadWrite，FileShare.ReadWrite）;
 

和

  Response.TransmitFile（apPath）;
 

似乎试图再次打开该文件。

我建议叫

  _FileStream.Close（）;
 

之前调用的TransmitFile 。

I'm new at web app in ASP.NET and I came across this problem.

I have a page whe there is a Button to download a template.xls that is previously stored at a SharePoint page. I have the download method and it's working just fine. The template in question is being saved where it should be, on a folder where my web app is located, on my local IIS. The problem is to open this file to the end user. I need a popup to be displayed to the user, so he can open/save this template.xls I'm using the following :

//path on my local IIS where the file is located after the download
string _strFolderApp = "~/Arq/";
string _strFullFolderApp = _strFolderApp + _strFileName;
string apPath = System.Web.Hosting.HostingEnvironment.MapPath(_strFullFolderApp);

FileStream _FileStream = new FileStream(apPath, FileMode.Create, FileAccess.ReadWrite, FileShare.ReadWrite);
// Writes a block of bytes to this stream using data from a byte array.
_FileStream.Write(_contentFile, 0, _contentFile.Length);

//opens the file
Response.Clear();
Response.AddHeader("content-disposition", "attachment; filename=" + _strFileName);
Response.ContentType = "";
Response.TransmitFile(apPath);
Response.Flush();
File.Delete(apPath);
Response.End();
# endregion

// close file stream
_FileStream.Close();

I searched online and all answers end up in using FileShare.ReadWrite so both process would work properly. But it's not working for me, because when the code reaches Response.TransmitFile(apPath); I get an exception and popup doesn't show. Exception :

The process cannot access the file 'c:\inetpub\wwwroot\MyWebApp\File\TemplateSharePoint.xlsx' because it is being used by another process.

Please any help would be appreciated :)

EDIT Code update

if (_flgSPSDownload)
        {
            System.IO.FileStream _FileStream = new System.IO.FileStream(apPath,System.IO.FileMode.Create, System.IO.FileAccess.Write);
            _FileStream.Write(_contentFile, 0, _contentFile.Length);
            _FileStream.Close();


            Response.Clear();
            Response.AddHeader("content-disposition", "attachment; filename=" + _strFileName);
            //Set the appropriate ContentType.
            Response.ContentType = "Application/x-msexcel";
            Response.TransmitFile(apPath);
            Response.Flush();
            //Write the file directly to the HTTP content output stream.
            Response.WriteFile(apPath);
            //File.Delete(apPath);

            //Process.Start(_strDestinationPath + "//" + _strFileName);

解决方案

From what I can tell, you're opening the file-stream, and then trying to open it again, before you close it.

Initial opening of the file:

FileStream _FileStream = new FileStream(apPath, FileMode.Create, FileAccess.ReadWrite, FileShare.ReadWrite);

and

Response.TransmitFile(apPath); 

seems to be trying to open the file again.

I would suggest calling

_FileStream.Close();

before calling TransmitFile.

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