Pig - 如何迭代一袋地图 [英] Pig - how to iterate on a bag of maps

问题描述

让我解释一下这个问题.我有这行代码:

u = FOREACH people GENERATE FLATTEN($0#'experiences') as j;倾倒你；

产生这个输出:

([id#1,date_begin#12 2012,description#blabla,date_end#04 2013],[id#2,date_begin#02 2011,description#blabla2,date_end#04 2013])([id#1,date_begin#12 2011,description#blabla3,date_end#04 2012],[id#2,date_begin#02 2010,description#blabla4,date_end#04 2011])

然后，当我这样做时:

p = foreach u generate j#'id', j#'description';转储 p;

我有这个输出:

(1,blabla)(1,blabla3)

但这不是我想要的.我想要这样的输出:

(1,blabla)(2,blabla2)(1,blabla3)(2,blabla4)

我怎么会有这个?

非常感谢.

解决方案

我假设您在 u 中 FLATTENing 的 $0 是一个元组.

总体问题是 j 只引用元组中的第一个映射.为了得到你想要的输出，你必须将每个元组转换成一个包，然后 FLATTEN 它.

如果你知道每个元组最多有两个映射，你可以这样做:

-- 我的 B 是你的你B = FOREACH A GENERATE (tuple(map[],map[]))$0#'experiences' AS T ;B2 = FOREACH B GENERATE FLATTEN(TOBAG(T.$0, T.$1)) AS j ;C = foreach B2 生成 j#'id', j#'description' ;

如果您不知道元组中有多少个字段，那么这将困难.

<小时>

注意:这适用于 pig 0.10.

对于具有未定义数量映射的元组，我能想到的最佳答案是使用 UDF 来解析字节数组:

myudf.py

@outputSchema('vals: {(val:map[])}')def foo(the_input):# 这将不确定数量的地图转换成一个包.foo = [chr(i) for i in the_input]foo = ''.join(foo).strip('()')出 = []对于 foo.split('],[') 中的 f:f = f.strip('[]')out.append(dict((k, v) for k, v in [ i.split('#') for i in f.split(',')]))回来

myscript.pig

使用 jython 作为 myudf 注册myudf.py"；B = FOREACH A GENERATE FLATTEN($0#'experiences');T1 = FOREACH B GENERATE FLATTEN(myudf.foo($0)) AS M ;T2 = FOREACH T1 GENERATE M#'id', M#'description';

然而，这依赖于 #、、 或 ],[ 不会出现在任何键或值中的事实在地图上.

<小时>

注意:这适用于 pig 0.11.

因此，在这种情况下，pig 处理 Python UDF 输入的方式似乎发生了变化.字节数组不是 foo 的输入，而是自动转换为适当的类型.在这种情况下，一切都会变得更容易:

myudf.py

@outputSchema('vals: {(val:map[])}')def foo(the_input):# 这将不确定数量的地图转换成一个包.出 = []对于 the_input 中的地图:out.append(地图)回来

myscript.pig

使用 jython 作为 myudf 注册myudf.py"；# 这次你应该传入整个元组.B = FOREACH A GENERATE $0#'experiences' ;T1 = FOREACH B GENERATE FLATTEN(myudf.foo($0)) AS M ;T2 = FOREACH T1 GENERATE M#'id', M#'description';

Let me explain the problem. I have this line of code:

u = FOREACH persons GENERATE FLATTEN($0#'experiences') as j;
dump u;

which produces this output:

([id#1,date_begin#12 2012,description#blabla,date_end#04 2013],[id#2,date_begin#02 2011,description#blabla2,date_end#04 2013])
([id#1,date_begin#12 2011,description#blabla3,date_end#04 2012],[id#2,date_begin#02 2010,description#blabla4,date_end#04 2011])

Then, when I do this:

p = foreach u generate j#'id', j#'description';
dump p;

I have this output:

(1,blabla)
(1,blabla3)

But that's not what I wanted. I would like to have an output like this:

(1,blabla)
(2,blabla2)
(1,blabla3)
(2,blabla4)

How could I have this ?

Thank you very much.

解决方案

I'm assuming that the $0 you are FLATTENing in u is a tuple.

The overall problem is that j is only referencing the first map in the tuple. In order to get the output you want, you'll have to convert each tuple into a bag, then FLATTEN it.

If you know that each tuple will have up to two maps, you can do:

-- My B is your u
B = FOREACH A GENERATE (tuple(map[],map[]))$0#'experiences' AS T ;
B2 = FOREACH B GENERATE FLATTEN(TOBAG(T.$0, T.$1)) AS j ;

C = foreach B2 generate j#'id', j#'description' ;

If you don't know how many fields will be in the tuple, then this is will be much harder.

---

NOTE: This works for pig 0.10.

For tuples with an undefined number of maps, the best answer I can think of is using a UDF to parse the bytearray:

myudf.py

@outputSchema('vals: {(val:map[])}')
def foo(the_input):
    # This converts the indeterminate number of maps into a bag.
    foo = [chr(i) for i in the_input]
    foo = ''.join(foo).strip('()')
    out = []
    for f in foo.split('],['):
        f = f.strip('[]')
        out.append(dict((k, v) for k, v in [ i.split('#') for i in f.split(',')]))
    return out

myscript.pig

register 'myudf.py' using jython as myudf ;
B = FOREACH A GENERATE FLATTEN($0#'experiences') ;

T1 = FOREACH B GENERATE FLATTEN(myudf.foo($0)) AS M ;
T2 = FOREACH T1 GENERATE M#'id', M#'description' ;

However, this relies on the fact that #, ,, or ],[ will not appear in any of the keys or values in the map.

---

NOTE: This works for pig 0.11.

So it seems that how pig handles the input to the python UDFs changed in this case. Instead of a bytearray being the input to foo, the bytearray is automatically converted to the appropriate type. In that case it makes everything much easier:

myudf.py

@outputSchema('vals: {(val:map[])}')
def foo(the_input):
    # This converts the indeterminate number of maps into a bag.
    out = []
    for map in the_input:
        out.append(map)
    return out

myscript.pig

register 'myudf.py' using jython as myudf ;

# This time you should pass in the entire tuple.
B = FOREACH A GENERATE $0#'experiences' ;

T1 = FOREACH B GENERATE FLATTEN(myudf.foo($0)) AS M ;
T2 = FOREACH T1 GENERATE M#'id', M#'description' ;

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