pyspark 中的 scala.util.Try 相当于什么? [英] What is the equivalent to scala.util.Try in pyspark?

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问题描述

我有一个糟糕的 HTTPD access_log,只想跳过糟糕"的行.

I've got a lousy HTTPD access_log and just want to skip the "lousy" lines.

在 Scala 中,这很简单:

In scala this is straightforward:

import scala.util.Try

val log = sc.textFile("access_log")

log.map(_.split(' ')).map(a => Try(a(8))).filter(_.isSuccess).map(_.get).map(code => (code,1)).reduceByKey(_ + _).collect()

对于python,我通过使用lambda"符号显式定义一个函数来获得以下解决方案:

For python I've got the following solution by explicitly defining a function in contrast using the "lambda" notation:

log = sc.textFile("access_log")

def wrapException(a):
    try:
        return a[8]
    except:
        return 'error'

log.map(lambda s : s.split(' ')).map(wrapException).filter(lambda s : s!='error').map(lambda code : (code,1)).reduceByKey(lambda acu,value : acu + value).collect()

在 pyspark 中是否有更好的方法(例如在 Scala 中)?

Is there a better way doing this (e.g. like in Scala) in pyspark?

非常感谢!

推荐答案

更好是一个主观术语,但您可以尝试一些方法.

Better is a subjective term but there are a few approaches you can try.

  • 在这种特殊情况下,您可以做的最简单的事情就是避免任何异常.您只需要一个 flatMap 和一些切片:

log.flatMap(lambda s : s.split(' ')[8:9])

如您所见,这意味着不需要异常处理或后续的filter.

As you can see it means no need for an exception handling or subsequent filter.

以前的想法可以用一个简单的包装器来扩展

Previous idea can be extended with a simple wrapper

def seq_try(f, *args, **kwargs):
    try:
        return [f(*args, **kwargs)]
    except:
        return []

和示例用法

from operator import div # FYI operator provides getitem as well.

rdd = sc.parallelize([1, 2, 0, 3, 0, 5, "foo"])

rdd.flatMap(lambda x: seq_try(div, 1., x)).collect()
## [1.0, 0.5, 0.3333333333333333, 0.2]

  • 终于有更多面向对象的方法了:

  • finally more OO approach:

    import inspect as _inspect
    
    class _Try(object): pass    
    
    class Failure(_Try):
        def __init__(self, e):
            if Exception not in _inspect.getmro(e.__class__):
                msg = "Invalid type for Failure: {0}"
                raise TypeError(msg.format(e.__class__))
            self._e = e
            self.isSuccess =  False
            self.isFailure = True
    
        def get(self): raise self._e
    
        def __repr__(self):
            return "Failure({0})".format(repr(self._e))
    
    class Success(_Try):
        def __init__(self, v):
            self._v = v
            self.isSuccess = True
            self.isFailure = False
    
        def get(self): return self._v
    
        def __repr__(self):
            return "Success({0})".format(repr(self._v))
    
    def Try(f, *args, **kwargs):
        try:
            return Success(f(*args, **kwargs))
        except Exception as e:
            return Failure(e)
    

    和示例用法:

    tries = rdd.map(lambda x: Try(div, 1.0, x))
    tries.collect()
    ## [Success(1.0),
    ##  Success(0.5),
    ##  Failure(ZeroDivisionError('float division by zero',)),
    ##  Success(0.3333333333333333),
    ##  Failure(ZeroDivisionError('float division by zero',)),
    ##  Success(0.2),
    ##  Failure(TypeError("unsupported operand type(s) for /: 'float' and 'str'",))]
    
    tries.filter(lambda x: x.isSuccess).map(lambda x: x.get()).collect()
    ## [1.0, 0.5, 0.3333333333333333, 0.2]
    

    您甚至可以将模式匹配与 multipledispatch

    You can even use pattern matching with multipledispatch

    from multipledispatch import dispatch
    from operator import getitem
    
    @dispatch(Success)
    def check(x): return "Another great success"
    
    @dispatch(Failure)
    def check(x): return "What a failure"
    
    a_list = [1, 2, 3]
    
    check(Try(getitem, a_list, 1))
    ## 'Another great success'
    
    check(Try(getitem, a_list, 10)) 
    ## 'What a failure'
    

    如果您喜欢这种方法,我已将更完整的实现推送到 GitHubpypi.

    If you like this approach I've pushed a little bit more complete implementation to GitHub and pypi.

    这篇关于pyspark 中的 scala.util.Try 相当于什么?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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