查看字符串是否包含不同数据帧中的子字符串 [英] looking if String contain a sub-string in differents Dataframes

查看:29
本文介绍了查看字符串是否包含不同数据帧中的子字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有 2 个数据框:

df_1,列 id 只包含字符和数字 ==> 归一化,id_no_normalized示例:

df_1, column id contain only characters and numbers ==> normalized, and id_no_normalized Example:

 id_normalized   |  id_no_normalized
    -------------|-------------------
    ABC          |  A_B.C
    -------------|-------------------
    ERFD         |  E.R_FD
    -------------|-------------------
    12ZED        |   12_Z.ED

df_2,列 name 只包含字符和数字 ==> 附有规范化

df_2, column name contain only characters and numbers ==> normalized are attached

示例:

name
----------------------------
googleisa12ZEDgoodnavigator
----------------------------
internetABCexplorer
----------------------------

如果 name (dataset_2) 中存在 id_normalized (dataset_1),我想查看它.如果我找到它,我就取 id_no_normalized 的值并将其存储在 dataset_2

I would like to look the id_normalized (dataset_1) if exist in name (dataset_2). If I find it, I take the value of id_no_normalized and I store it in a new column in dataset_2

预期结果:

   name                         |   result
    ----------------------------|----------
    googleisa12ZEDgoodnavigator |  12_Z.ED
    ----------------------------|----------
    internetABCexplorer         |  A_B.C
    ----------------------------|----------

我是用这个代码做到的:

I did it using this code:

df_result = df_2.withColumn("id_no_normalized", dft_2.name.contains(df_1.id_normalized))
    return df_result.select("name", "id_normalized")

不起作用,因为它在 df_2 中找不到 id_normalized.

is not working because, it doesn't find the id_normalized in the df_2.

Second solution, it work only when I limited the output on 300 rows almost, but when I return all the data, is took many time running and not finish:

   df_1 = df_1.select("id_no_normalized").drop_duplicates()
df_1 = df_1.withColumn(
    "id_normalized",
    F.regexp_replace(F.col("id_no_normalized"), "[^a-zA-Z0-9]+", ""))
df_2 = df_2.select("name")
extract = F.expr('position(id_normalized IN name)>0')
result = df_1.join(df_2, extract)
return result

如何更正我的代码以解决它?谢谢

How can I correct my code to resolve it ? Thank you

推荐答案

我们可以使用交叉连接并在新的 DF 上应用 UDF 来解决这个问题,但我们再次需要确保它适用于大数据集.

We can solve this using cross join and applying UDF on new DF, but again we need to ensure it works on a big dataset.

from pyspark.sql.functions import udf
from pyspark.sql.types import IntegerType

data1 = [
 {"id_normalized":"ABC","id_no_normalized":"A_B.C"},
 {"id_normalized":"ERFD","id_no_normalized":"E.R_FD"},
 {"id_normalized":"12ZED","id_no_normalized":"12_Z.ED"}
]

data2 = [
 {"name": "googleisa12ZEDgoodnavigator"},
 {"name": "internetABCexplorer"}
]

df1 = spark.createDataFrame(data1, ["id_no_normalized", "id_normalized"])
df2 = spark.createDataFrame(data2, ["name"])

df3 = df1.crossJoin(df2)
search_for_udf = udf(lambda name,id_normalized: name.find(id_normalized), returnType=IntegerType())
df4 = df3.withColumn("contain", search_for_udf(df3["name"], df3["id_normalized"]))
df4.filter(df4["contain"] > -1).show()


>>> df4.filter(df4["contain"] > -1).show()
+----------------+-------------+--------------------+-------+
|id_no_normalized|id_normalized|                name|contain|
+----------------+-------------+--------------------+-------+
|           A_B.C|          ABC| internetABCexplorer|      8|
|         12_Z.ED|        12ZED|googleisa12ZEDgoo...|      9|
+----------------+-------------+--------------------+-------+

我相信有一些 Spark 技术可用于提高交叉连接的效率.

I believe there are some spark techniques available to make cross join efficient.

这篇关于查看字符串是否包含不同数据帧中的子字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆