如何在 R 中将 groupedData 转换为 Dataframe [英] How can I convert groupedData into Dataframe in R

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问题描述

考虑我有以下数据框

AccountId,CloseDate
1,2015-05-07
2,2015-05-09
3,2015-05-01
4,2015-05-07
1,2015-05-09
1,2015-05-12
2,2015-05-12
3,2015-05-01
3,2015-05-01
3,2015-05-02
4,2015-05-17
1,2015-05-12

我想根据 AccountId 对其进行分组,然后我想添加另一个名为 date_diff 的列,该列将包含当前行和前一行之间 CloseDate 的差异.请注意,我希望仅针对具有相同 AccountId 的行计算此 date_diff.所以我需要在添加另一列之前对数据进行分组

I want to group it based on AccountId and then I want to add another column naming date_diff which will contain the difference in CloseDate between the current row and previous row. Please note that I want this date_diff to be calculated only for rows having same AccountId. So I need to group the data before adding another column

下面是我使用的R代码

  df <- read.df(sqlContext, "/home/ubuntu/work/csv/sample.csv", source = "com.databricks.spark.csv", inferSchema = "true", header="true")
  df$CloseDate <- to_date(df$CloseDate)
  groupedData <- SparkR::group_by(df, df$AccountId)
  SparkR::mutate(groupedData, DiffCloseDt = as.numeric(SparkR::datediff((CloseDate),(SparkR::lag(CloseDate,1)))))

要添加另一列,我正在使用 mutate.但是当 group_by 返回 groupedData 时,我无法在这里使用 mutate .我收到以下错误

To add another column I am using mutate. But as the group_by returns groupedData I am not able to use mutate here. I am getting the below error

 Error in (function (classes, fdef, mtable)  : 
  unable to find an inherited method for function ‘mutate’ for signature ‘"GroupedData"’

那么如何将 GroupedData 转换为 Dataframe 以便我可以使用 mutate 添加列?

So how can I convert GroupedData into Dataframe so that I can add columns using mutate?

推荐答案

使用 group_by 无法实现您想要的.正如已经在 SO 上多次解释的那样:

What you want is not possible to achieve using group_by. As already explained quite a few times on SO :

group_by 不会对数据进行物理分组.此外,应用 group_by 后的操作顺序是不确定的.

group_by on a DataFrame doesn't physical group the data. Moreover order of operations after applying group_by is nondeterministic.

要获得所需的输出,您必须使用窗口函数并提供明确的排序:

To achieve desired output you'll have to use window functions and provide an explicit ordering:

df <- structure(list(AccountId = c(1L, 2L, 3L, 4L, 1L, 1L, 2L, 3L, 
  3L, 3L, 4L, 1L), CloseDate = structure(c(3L, 4L, 1L, 3L, 4L, 
  5L, 5L, 1L, 1L, 2L, 6L, 5L), .Label = c("2015-05-01", "2015-05-02", 
  "2015-05-07", "2015-05-09", "2015-05-12", "2015-05-17"), class = "factor")), 
  .Names = c("AccountId", "CloseDate"),
  class = "data.frame", row.names = c(NA, -12L))

hiveContext <- sparkRHive.init(sc)
sdf <- createDataFrame(hiveContext, df)
registerTempTable(sdf, "df")

query <- "SELECT *, LAG(CloseDate, 1) OVER (
  PARTITION BY AccountId ORDER BY CloseDate
) AS DateLag FROM df"

dfWithLag <- sql(hiveContext, query)

withColumn(dfWithLag, "diff", datediff(dfWithLag$CloseDate, dfWithLag$DateLag)) %>%
  head()

##   AccountId  CloseDate    DateLag diff
## 1         1 2015-05-07       <NA>   NA
## 2         1 2015-05-09 2015-05-07    2
## 3         1 2015-05-12 2015-05-09    3
## 4         1 2015-05-12 2015-05-12    0
## 5         2 2015-05-09       <NA>   NA
## 6         2 2015-05-12 2015-05-09    3

这篇关于如何在 R 中将 groupedData 转换为 Dataframe的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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