将 GUID 结构转换为 LPCSTR [英] Convert GUID structure to LPCSTR

问题描述

我正在 C 中使用 Win32 API，并且需要将 GUID 结构转换为 LPCSTR.我对 Win32 比较陌生，没有找到关于这种类型转换的太多信息.

I am working with Win32 API in C and have a need to convert a GUID structure into LPCSTR. I am relatively new to Win32 and didn't find much information around this type of conversion.

我确实设法使用 StringFromGUID2 函数(请参阅下面的代码片段)将 GUID 转换为 OLECHAR，但仍坚持进一步转换为 LPSCSTR.我不太确定我使用 OLECHAR 朝着正确的方向前进，但目前看来这样做是合乎逻辑的.

I did manage to convert GUID to OLECHAR using StringFromGUID2 function (see code fragment below) but stuck on further conversion to LPSCSTR. I am not too sure I am heading in the correct direction with OLECHAR but at the moment it seems logical thing to do.

GUID guid;
OLECHAR wszGuid[40] = {0};
OLECHAR szGuid[40]={0};
LPCSTR lpcGuid;
CoCreateGuid(&guid);
StringFromGUID2(&guid, wszGuid, _countof(wszGuid));

推荐答案

操作系统不支持直接将 GUID 格式化为 Ansi 字符串.您可以先将其格式化为 Unicode 字符串，然后再将其转换为 Ansi:

The OS does not support formatting a GUID as an Ansi string directly. You can format it as a Unicode string first and then convert it to Ansi afterwards:

GUID guid = {0};
wchar_t szGuidW[40] = {0};
char szGuidA[40] = {0};
CoCreateGuid(&guid);
StringFromGUID2(&guid, szGuidW, 40);
WideCharToMultiByte(CP_ACP, 0, szGuidW, -1, szGuidA, 40, NULL, NULL);

或者您可以使用 sprintf() 或类似的函数来手动格式化 Ansi 字符串:

Or you can use sprintf() or similar function to format the Ansi string manually:

GUID guid = {0};
char szGuid[40]={0};
CoCreateGuid(&guid);
sprintf(szGuid, "{%08X-%04X-%04X-%02X%02X-%02X%02X%02X%02X%02X%02X}", guid.Data1, guid.Data2, guid.Data3, guid.Data4[0], guid.Data4[1], guid.Data4[2], guid.Data4[3], guid.Data4[4], guid.Data4[5], guid.Data4[6], guid.Data4[7]);

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