ASP.NET普通防爆pression验证（密码强度） [英] ASP.NET Regular Expression Validator (Password Strength)
问题描述
我有一个具有以下前pression验证控件：
I have a validation control that has the following expression:
(?=(.*\\d.*){2,})(?=(.*\\w.*){2,})(?=(.*\\W.*){1,}).{8,}
这是至少有 2位数 2字母字符 1非字母数字和 8个字符的最小。不幸的是这似乎并不为跨浏览器兼容。
That's a password with at least 2 digits, 2 alpha characters, 1 non-alphanumeric and 8 character minimum. Unfortunately this doesn't seem to be cross-browser compliant.
此验证工作完全在Firefox，但它在Internet Explorer中没有。
This validation works perfectly in Firefox, but it does not in Internet Explorer.
您的每一个答案结果的组合：的
A combination of each of your answers results in:
var format = "^(?=.{" + minLength + ",})" +
(minAlpha > 0 ? "(?=(.*[A-Za-z].*){" + minAlpha + ",})" : "") +
(minNum > 0 ? "(?=(.*[0-9].*){" + minNum + ",})" : "") +
(minNonAlpha > 0 ? "(?=(.*\\W.*){" + minNonAlpha + ",})" : "") + ".*$";
EX: "^(?=.{x,})(?=(.*[A-Za-z].*){y,})(?=(.*[0-9].*){z,})(?=(.*\W.*){a,}).*$"
重要件具有（？{X，}）为长度第一
推荐答案
（？=（。* \\ W。*）{0，}）不为0的非-字母数字字符。它的至少0 的非字母数字字符。如果你想要的密码，不包含任何非字母数字字符，你可以做任何（？！。* \\ W）或（？= \\ w * $）。
(?=(.*\W.*){0,}) is not 0 non-alphanumeric characters. It is at least 0 non-alphanumeric characters. If you wanted the password to not contain any non-alphanumeric characters you could do either (?!.*\W) or (?=\w*$).
有一个简单的解决方案将是跳过 \\ W 前瞻，并使用 \\ W {8} 而不是 {8} 。
A simpler solution would be to skip the \W look-ahead, and use \w{8,} instead of .{8,}.
此外， \\ W 包括 \\ D 。如果你想只阿尔法你可以做任何 [^ \\ W \\ D] 或 [A-ZA-Z] 。
Also, \w includes \d. If you wanted just the alpha you could do either [^\W\d] or [A-Za-z].
/^(?=(?:.*?\d){2})(?=(?:.*?[A-Za-z]){2})\w{8,}$/
这将验证密码至少包含两位 两位阿尔法，是是在至少8个字符长，并包含<强>仅字母数字字符（包括下划线）。
This would validate the password to contain at least two digits, two alphas, be at least 8 characters long, and contain only alpha-numeric characters (including underscore).
-
\\ W=[A-ZA-Z0-9 _] -
\\ D=[0-9] -
\\ S=[\\ t \\ n \\ r \\ F \\ V]
\w=[A-Za-z0-9_]\d=[0-9]\s=[ \t\n\r\f\v]
编辑：
在所有浏览器使用这个你可能需要做这样的事情：
To use this in all browsers you probably need to do something like this:
var re = new RegExp("^(?=(?:.*?\\d){2})(?=(?:.*?[A-Za-z]){2})\\w{8,}$");
if (re.test(password)) { /* ok */ }
EDIT2：近期讨论的更新我的全部答案几乎无效。 ^^ ;;
The recent update in the question almost invalidates my whole answer. ^^;;
您应该仍然能够使用JavaScript code在最后，如果你与你有什么替代原先的格局。
You should still be able to use the JavaScript code in the end, if you replace the pattern with what you had originally.
EDIT3：确定。现在我明白你的意思。
OK. Now I see what you mean.
/^(?=.*[a-z].*[a-z])(?=.*[0-9].*[0-9]).{3,}/.test("password123") // matches
/^(?=.*[a-z].*[a-z])(?=.*[0-9].*[0-9]).{4,}/.test("password123") // does not match
/^(?=.*[a-z].*[a-z]).{4,}/.test("password123") // matches
这似乎（？=）是不是真的零宽度在Internet Explorer中。
It seems (?= ) isn't really zero-width in Internet Explorer.
<一个href=\"http://development.thatoneplace.net/2008/05/bug-discovered-in-internet-explorer-7.html\">http://development.thatoneplace.net/2008/05/bug-discovered-in-internet-explorer-7.html
Edit4：更多阅读：<一href=\"http://blog.stevenlevithan.com/archives/regex-lookahead-bug\">http://blog.stevenlevithan.com/archives/regex-lookahead-bug
我认为这能解决你的问题：
I think this can solve your problem:
/^(?=.{8,}$)(?=(?:.*?\d){2})(?=(?:.*?[A-Za-z]){2})(?=(?:.*?\W){1})/
new RegExp("^(?=.{8,}$)(?=(?:.*?\\d){2})(?=(?:.*?[A-Za-z]){2})(?=(?:.*?\\W){1})")
的（？= {8} $）需要是第一位的。
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