删除附加脚本 javascript [英] remove appended script javascript

问题描述

我如何删除我附加的脚本，因为它会导致我的应用出现一些问题.

这是我获取脚本的代码

var nowDate = new Date().getTime();var url = val.redirect_uri + "notify.js?nocache=" + nowDate + "&callback=dummy";var script = document.createElement('script');脚本.src = url;document.body.appendChild(script);

然后我有一个自动加载功能，这会导致创建另一个元素脚本.

我想删除在添加另一个元素之前附加的前一个元素.

解决方案

我又做了一些测试，在你得到问题的正确答案之前(希望有一个)，你可以试试这个:

 ShowHTML<脚本>(函数 foo(){var b=function moo(){var c=document.getElementsByTagName('script');警报(document.body.innerHTML)；c[0].parentElement.removeChild(c[0]);警报(document.body.innerHTML)；}var a=setTimeout(b,1000);b=空；})();富=空；

这只是一个测试代码，但它包含了一个想法，你可以如何解决这个问题.它从 DOM 中删除 ，最后一行破坏了脚本的所有功能.

(代码也有一点细节，这表明，setTimeout 会做 eval()，不管它是如何论证的......?)

how can I remove my appended script because it causes some problems in my app.

This is my code to get my script

var nowDate = new Date().getTime();
var url = val.redirect_uri + "notify.js?nocache=" + nowDate + "&callback=dummy";
var script = document.createElement('script');
script.src = url;
document.body.appendChild(script);

Then I have an auto load function, that causes to create another element script.

I want to get rid of the previous element that was appended before another element is added.

解决方案

I did some more tests, and before you'll get a correct answer to your question (hope there is a one) you can try this:

<button onclick="foo()">ShowHTML</button>
<script>
(function foo(){
    var b=function moo(){
        var c=document.getElementsByTagName('script');
        alert(document.body.innerHTML);
        c[0].parentElement.removeChild(c[0]);
        alert(document.body.innerHTML);
    }
    var a=setTimeout(b,1000);
    b=null;
})();
foo=null;
</script>

This is just a test code, but it contains an idea, how you possible could solve the problem. It removes <sript> from the DOM, and the last line destroys all functionality of the script.

(The code also has a little detail, which shows, that setTimeout will do eval(), no matter how it is argumented...?)

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