如何使用 ndb 中重复字符串属性的列表对象进行查询 [英] How to query with a list object on repeated string property in ndb
问题描述
通过谷歌应用引擎,我使用 ndb 来管理我的数据.我有一个使用重复字符串属性来保存字符串值列表的实体.如何使用等于属性值的列表对象进行查询?
With google app engine, I use ndb to manange my data. I have a entity that use a repeated string property to save a list of string values. How can I query with a list object that is equal to the property value?
我的意思是,实体是
class Question(ndb.Model):
question = ndb.StringProperty(required=True)
choices = ndb.StringProperty(repeated=True)
我想这样查询:
question = "The question"
choices = ["Choice1", "Choice2", ..., "Choice6"]
Question.query(Question.question==question, Question.choices==choices)
推荐答案
当你有一个重复的属性时,没有办法执行查询来搜索该列表的完全相等性.
When you have a repeated property, there is no way to perform a query searching for exact equality of that list.
例如,带有以下内容的 Question 实体:
For example, a Question entity with:
question = "A question"
choices = ["A", "B", "C"]
将匹配所有以下查询
Question.query(Question.choices=="A")
Question.query(Question.choices=="B")
Question.query(Question.choices=="C")
<小时>
解决方案 1:计算属性
Solution 1: Computed Property
如果你想写一个整个列表相等的查询,你可以使用一个计算属性,它是重复属性的字符串化版本:
If you want to write a query where the entire list is equal, you could use a computed property that is a stringified version of your repeated property:
class Question(ndb.Model):
question = ndb.StringProperty(required=True)
choices = ndb.StringProperty(repeated=True)
choices_list = ndb.ComputedProperty(lambda self: return ",".join(self.choices))
然后使用choices_list
查询:
choices = [...]
Question.query(Question.choices_list==",".join(choices))
当然,这只会在 choices
完全匹配(包括顺序)时匹配.
Of course, this will only match if the choices
match exactly (including order).
解决方案 2:使用 AND
Solution 2: Using AND
您也可以使用 AND 查询:
You could also use an AND query:
choices = [...]
Questions.query(
ndb.AND(Question.choices==choices[0],
....,
Question.choices==choices[n])) # Do this in a programmatic way
此解决方案的优点是列表的顺序无关紧要,但它可能会导致误报,因为对 ["A", "B"] 的查询将匹配具有选项 ["A",B",C"].
This solution has the upside that the ordering of your list does not matter, however it may result in false positives, as a query for ["A", "B"] will match an entity with choices ["A", "B", "C"].
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