更改 pandas 列中的数字字符串 [英] Alter number string in pandas column

问题描述

背景

我有一个示例 df，其中 Text 列包含 0,1 或 >1 ABC's

I have a sample df with a Text column containing 0,1, or >1 ABC's

import pandas as pd
df = pd.DataFrame({'Text' : ['Jon J Mmith  ABC: 1111111 is this here', 
                                   'ABC: 1234567 Mary Lisa Rider found here', 
                                   'Jane A Doe is also here',
                                'ABC: 2222222 Tom T Tucker is here ABC: 2222222 too'], 

                      'P_ID': [1,2,3,4],
                      'N_ID' : ['A1', 'A2', 'A3', 'A4']

                     })

#rearrange columns
df = df[['Text','N_ID', 'P_ID']]
df

                            Text                      N_ID  P_ID
0   Jon J Mmith ABC: 1111111 is this here               A1  1
1   ABC: 1234567 Mary Lisa Rider found here             A2  2
2   Jane A Doe is also here                             A3  3
3   ABC: 2222222 Tom T Tucker is here ABC: 2222222...   A4  4  

目标

1) 将Text 列中的ABC 数字(例如ABC: 1111111)更改为ABC: **BLOCK**

1) Change the ABC numbers in Text column (e.g ABC: 1111111) to ABC: **BLOCK**

2) 创建一个包含此输出的新列 Text_ABC

2) Create a new column Text_ABC containing this output

期望输出

                             Text                  N_ID P_ID Text_ABC
0   Jon J Mmith ABC: 1111111 is this here          A1   1   Jon J Mmith ABC: **BLOCK** is this here
1   ABC: 1234567 Mary Lisa Rider found here        A2   2   ABC: **BLOCK** Mary Lisa Hider found here   
2   Jane A Doe is also here                        A3   3   Jane A Doe is also here 
3   ABC: 2222222 Tom T Tucker is here ABC: 2222222 A4   4   ABC: **BLOCK** Tom T Tucker is here ABC: **BLOCK**

问题

如何实现我想要的输出?

How do I achieve my desired output?

推荐答案

如果你的所有数字都被替换，你可以这样做:

If all your numerics are to be replaced, you can do:

df['Text_ABC'] = df['Text'].replace(r'\d+', '***BLOCK***', regex=True)

但如果你想更具体，只替换ABC:之后的数字，那么你可以使用这个:

But if you want to be more specific and only replace the numerics after ABC:, then you can use this:

df['Text_ABC'] = df['Text'].replace(r'ABC: \d+', 'ABC: ***BLOCK***', regex=True)

给你:

df
                                                Text  P_ID N_ID                                           Text_ABC
0             Jon J Smith  ABC: 1111111 is this here     1   A1           Jon J Smith  ABC: ***BLOCK*** is this here
1            ABC: 1234567 Mary Lisa Rider found here     2   A2          ABC: ***BLOCK*** Mary Lisa Rider found here
2                            Jane A Doe is also here     3   A3                            Jane A Doe is also here
3  ABC: 2222222 Tom T Tucker is here ABC: 2222222...     4   A4  ABC: ***BLOCK*** Tom T Tucker is here ABC: ***BLOCK...

作为正则表达式，\d+ 表示匹配一个或多个连续数字"，因此在 replace 表示用 ***BLOCK* 替换一个或多个连续数字**"

As a regex, \d+ means "match one or more consecutive digits", so using that within replace says to "replace one or more consecutive digits with ***BLOCK***"

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