Python ConfigParser 问题 [英] Python ConfigParser Question

问题描述

ConfigParser 的配置文件是否必须命名为Config.ini"才能工作?

我希望名称为1Config.ini"，以便它出现在文件夹目录的顶部.

这是我目前拥有的

config = ConfigParser.ConfigParser()config.read(Revision[0:Revision.rfind('\\')] + "\1Config.ini")Type = config.get("myvars", "Type")

但是当文件和代码命名为1Config.ini"时，我收到此错误

:没有部分:'myvars'

解决方案

下面的输出是什么?确保它是一个有效的文件名.

<预><代码>>>>打印修订版[0:Revision.rfind('\\')] + "\1Config.ini"

最好使用 os.path.join 而不是连接字符串:

导入操作系统文件名 = os.path.join(Revision[0:Revision.rfind('\\')], "Config.ini")config.read(文件名)

您可能不应该将变量命名为 Type，因为 type 是一个内置函数/模块，它会令人困惑.

Type = config.get("myvars", "Type")

不，配置文件可以任意命名:

<预><代码>>>>a = ConfigParser.ConfigParser()>>>a.read("E:/Documents/2012/config.test") # 其中 config.test 是文档中的示例['E:/Documents/2012/config.test']>>>a.sections()['我的部分']>>>a.items(a.sections()[0])[('foodir', 'frob/whatever'),('dir', 'frob'),('long', '这个值在下一行继续\nin')]

Does the Config file for the ConfigParser have to be named "Config.ini" in order to work?

I want the name to be "1Config.ini" so that it appears at the top of a folder dir.

This is what I have currently

config = ConfigParser.ConfigParser()
config.read(Revision[0:Revision.rfind('\\')] + "\1Config.ini")

Type = config.get("myvars", "Type")

I get this error however when the file and code is named "1Config.ini"

<class 'ConfigParser.NoSectionError'>: No section: 'myvars'

解决方案

What's the output of the following? Make sure it's a valid file name.

>>> print Revision[0:Revision.rfind('\\')] + "\1Config.ini"

Ideally use os.path.join instead of concatenating strings:

import os
filename = os.path.join(Revision[0:Revision.rfind('\\')], "Config.ini")
config.read(filename)

You probably shouldn't name your variable Type, because type is a built-in function/module and it'd be confusing.

Type = config.get("myvars", "Type")

And no, config files can be named anything:

>>> a = ConfigParser.ConfigParser()
>>> a.read("E:/Documents/2012/config.test") # where config.test is the example from the documentation
['E:/Documents/2012/config.test']
>>> a.sections()
['My Section']
>>> a.items(a.sections()[0])
[('foodir', 'frob/whatever'),
 ('dir', 'frob'),
 ('long', 'this value continues\nin the next line')]

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