递增数组值 - Arduino [英] Incrementing array values - Arduino

问题描述

我正在尝试增加一些数组值:

I'm trying to increment some array values:

int counter[] = {0,0,0,0,0,0,0,0};

如果位置 0 中的数字值达到 25，则位置 1 中的值增加 1，位置 0 重置为 0.依此类推 - 当索引位置 2 达到 25 时，位置 3 增加 1，并将它自己的值重置为 0.

If the value of the number in position 0 reaches 25, then the value in position 1 is incremented by 1, and position 0 reset to 0. And so on - when index position 2 reaches 25 it increments position 3 by 1, and resets it's own value to 0.

我正在做一些 base26 递增 - 为给定数量的字母生成所有字母组合.理想情况下，我希望它无限地工作(理论上) - 当最后一个值达到 25 时附加一个新的数组索引.

I'm doing some base26 incrementing - generating all the combinations of letters for a given number of letters. Ideally I'd like this to work infinitely (in theory) - a new array index is appended when the last value reaches 25.

我正在研究与上一个问题相关的项目 - 可能会澄清我正在尝试做的事情:字母表的每个排列最多 29 个字符?

I'm working on the project which this previous question relates to - might clear up what I'm trying to do: Every permutation of the alphabet up to 29 characters?

这是我现在的代码:

// Set the variables.
String neologism;
int counter[] = {0,0,0,0,0,0,0,0};
String base26[] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

void setup() {
    // Initialize serial communication:
    Serial.begin(9600);
}

void loop() {
    int i = 0;
    // Reset or increment the counter.
    if (counter[i] == 25) {
        counter[i] = 0;
        counter[i+1]++;
    }
    else {
        counter[i]++;
    }
    neologism = letters(counter[i]);
    Serial.print(neologism+'\n');
    delay(100);
    i++;
    if(i>7) {
        i=0;
    }
}

String letters(int counter) {
    String newword;
    for(int i=0; i <= 7; i++) {
        newword += base26[counter];
    }
    return newword;
}

推荐答案

使用 类 java.math.BigInteger.

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