如何定义可变参数函数 [英] How to define a variadic function
问题描述
我正在寻找类似于 Javascript 的 arguments
数组的东西:
I'm looking for something similar to Javascript's arguments
array:
function parent(){
child.apply(this.arguments);
}
我知道可变参数长度的点符号以及方案的 apply
函数.
I'm aware of the dot notation for variable argument lengths and also scheme's apply
function.
这似乎不起作用,因为点被视为第一个参数:
This doesn't seem to work as the dot is taken to be the first argument:
(define (parent .)
(list .))
(parent 1 3 4 6 7)
Error: bad argument count - received 5 but expected 1: #<procedure (array arg-list)>
这可行,但并不理想.我想在没有额外语法的情况下调用函数来定义 args 列表:
This works but isn't ideal. I'd like to call the function without the extra syntax to define the args list:
(define (parent args-list)
(apply list args-list))
(parent 1 3 4 6 7)
Error: bad argument count - received 5 but expected 1: #<procedure (array args-list)>
(parent `(1 3 4 6 7))
(1 3 4 6 7)
推荐答案
正确的语法是:
(define (parent . args-list)
<do something with args-list>)
像这样使用它:
(parent 1 2 3 4 5)
在程序内部,所有参数都将绑定到一个名为args-list
的列表中.在上面的代码段中,args-list
将 '(1 2 3 4 5)
作为它的值.这是在 Scheme 中可变参数函数如何工作的一个例子.
Inside the procedure, all the arguments will be bound to a list named args-list
. In the above snippet, args-list
will have '(1 2 3 4 5)
as its value. This is an example of how variadic functions work in Scheme.
为了完整起见,同样的机制也可以用于匿名函数(注意args-list
不是被括号包围):
For the sake of completeness, the same mechanism can be used for anonymous functions, too (notice that args-list
is not surrounded by parenthesis):
((lambda args-list <do something with args-list>) 1 2 3 4 5)
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