C++ - main 的参数 [英] C++ - arguments to main

问题描述

非常基本的问题.我尝试编写一个程序，输出拖到 exe 上的文件的文件名.

very basic question. i try to write a program that outputs the filenames of the files dragged onto the exe.

我遵循本指南的主要论点:http://publications.gbdirect.co.uk/c_book/chapter10/arguments_to_main.html

i followed this guide for main arguments: http://publications.gbdirect.co.uk/c_book/chapter10/arguments_to_main.html

这是我的代码:

#include "stdafx.h"
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
    cout<<"num arguments: "<<argc<<"\n";

    while(argc--)
        printf("%s\n", *argv++);

    cout<<"press any key";
    getchar();
    return 0;
}

但它的输出是:

如果我运行它而不将文件拖放到 exe 上:

if i run it without dragging&dropping files onto the exe:

参数个数:1

G

按任意键

如果我拖放 3 个文件，它将输出:

if i drag&drop 3 files it will output:

参数个数:4

G

G

G

G

按任意键

既不是应用程序名称，也不是任何文件的名称以G"开头

neither the application name, nor the name of any of the files starts with "G"

有什么问题吗?

谢谢！

推荐答案

你只能得到第一个字母，因为你混合了 Unicode 而不是.抱歉，我无法解释 Gs(除非您的所有文件都在驱动器 G 上:?)但您会看到带有

You're only getting the first letter because you're mixing Unicode and not. I can't explain the Gs sorry (unless all your files are on drive G:?) but you'll see the full filenames with

while(argc--)
    _tprintf(_T("%s\n"), *argv++);

相反.

事后考虑，并被 sbi 的回答打败了:我找不到 _tcout 用作

Afterthought, and beaten to it by sbi's answer: I can't find a _tcout to use as

_tcout << *argv++;

相反，如果您想保留 C++ - 我想您必须定义一个，例如

instead if you wanted to stay C++ - I guess you'd have to define one, e.g.

#ifdef _UNICODE
#define _tcin wcin
#define _tcout wcout
#define _tcerr wcerr
#define _tclog wclog
#else
#define _tcin cin
#define _tcout cout
#define _tcerr cerr
#define _tclog clog
#endif

虽然这是 C++，但它们可能不应该被定义，而是其他的东西，而且我不能 100% 确定是什么.

although this being C++ they probably shouldn't be defines but something else, and I'm not 100% sure what.

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