VST/VLD 实际上是做什么的? [英] What VST/VLD actually do?

问题描述

下面两行代码到底会发生什么?

What exactly will happen with below 2 lines of code?

vst1.64 {d8, d9, d10, d11}, [r4:128]!
vst1.64 {d12, d13, d14, d15}, [r4:128]

更一般地说，我想知道什么是 VST &VLD 从 doc 开始:ARM 信息中心不要给我说清楚.

More generally, I want to know what VST & VLD do since doc from: ARM InfoCenter doesn't make it clear for me.

推荐答案

vst1.64 {d8, d9, d10, d11}, [r4:128]!

该指令将寄存器 d8、d9、d10 和 d11 的内容存储在 r4 指向的位置.该位置被暗示与 128 位边界对齐.之后 r4 将增加存储的字节数.在您的情况下，这些将是 32(四倍于 8 个字节)

This instruction stores the content of the registers d8, d9, d10 and d11 at the location pointed by r4. This location is hinted to be aligned to a 128 bit boundary. Afterwards r4 will be incremented by the amount of bytes stored. These would be 32 (four times 8 bytes) in your case

vst1.64 {d12, d13, d14, d15}, [r4:128]

该指令与上面的相同，但存储 d12、d13、d14 和 d15.R4 不会增加而是留在原处.

This instruction does the same as the above but stores d12, d13, d14 and d15. R4 will not be incremented but left where it is.

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