如何使用比较器对 ArrayList 进行排序? [英] How to sort ArrayList using Comparator?
问题描述
我有一个实现静态方法的学生类
I have a Class Student that Implements a static method
public static Comparator<Student> getCompByName()
为 Student 返回一个新的比较器对象,该对象比较 2 个 Students 对象通过属性名称".
that returns a new comparator object for Student that compares 2 Students objects by the attribute 'name'.
我现在需要通过使用我的函数 getCompByName() 按姓名"对学生 ArrayList 进行排序来测试这一点.
I need to now test this by sorting a students ArrayList by 'name' using my function getCompByName().
这是我在 Student 类中的 Comparator 方法.
Here is my Comparator method in my Student class.
public static Comparator<Student> getCompByName()
{
Comparator comp = new Comparator<Student>(){
@Override
public int compare(Student s1, Student s2)
{
return s1.name.compareTo(s2.name);
}
};
return comp;
}
我需要测试的主要部分
public static void main(String[] args)
{
// TODO code application logic here
//--------Student Class Test-------------------------------------------
ArrayList<Student> students = new ArrayList();
Student s1 = new Student("Mike");
Student s2 = new Student("Hector");
Student s3 = new Student("Reggie");
Student s4 = new Student("zark");
students.add(s1);
students.add(s2);
students.add(s3);
students.add(S4);
//Use getCompByName() from Student class to sort students
谁能告诉我我将如何使用主文件中的 getCompByName() 来实际按名称对 ArrayList 进行排序?我是比较器的新手,很难使用它们.该方法返回一个比较器,所以我不确定这将如何实现.我知道我需要使用 getCompByName() 进行排序,我只是不确定如何实现它.
Can anyone show me how I would use the getCompByName() in my main to actually sort the ArrayList by name? Im new to comparators and having a hard time with their usages. The method returns a comparator, so Im not sure how this will be implemented. I know I need to use getCompByName() to sort, im just not sure how to implement it.
推荐答案
使用 Collections.sort(List, Comparator) 方法:
Collections.sort(students, Student.getCompByName());
同样在你的代码中,在声明 List
时最好使用 List
接口:
Also in your code it would be good to use the List
interface when declaring the List
:
List<Student> students = new ArrayList();
您还可以通过使用 Student[]
并将其传递给 ArrayList
构造函数来收紧代码:
You could also tighten up the code by using a Student[]
and passing it to the ArrayList
constructor:
public static void main(String[] args) {
Student[] studentArr = new Student[]{new Student("Mike"),new Student("Hector"), new Student("Reggie"),new Student("zark")};
List<Student> students = new ArrayList<Student>(Arrays.asList(studentArr));
Collections.sort(students, Student.getCompByName());
for(Student student:students){
System.out.println(student.getName());
}
}
这是一个完整源代码的要点.
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