如何在不重复数字的情况下使此代码工作? [英] How to make this code work without repeating the numbers?

问题描述

我需要以随机顺序打印从 1 到 50 的数字而不重复它.

I need to print numbers from 1 to 50 in random order without repeating it .

static void Main(string[] args)
{
     ArrayList r = new ArrayList();

     Random ran = new Random();      
     for (int i = 0; i < 50; i++)
     {
        r.Add(ran.Next(1,51));

     }

     for (int i = 0; i < 50; i++)
        Console.WriteLine(r[i]);
     Console.ReadKey();
}

推荐答案

您需要做的就是检查该号码是否已存在于列表中，如果存在，则获取另一个:

All you need to do is this check if the number already exists in the list and if so get another one:

static void Main(string[] args)
{
    ArrayList r = new ArrayList();

    Random ran = new Random();      
    int num = 0;

    for (int i = 0; i < 50; i++)
    {
        do { num = ran.Next(1, 51); } while (r.Contains(num));
        r.Add(num);
    }

    for (int i = 0; i < 50; i++)
       Console.WriteLine(r[i]);

    Console.ReadKey();
}

这将大大提高效率，防止等待非冲突数的长时间停顿:

This will greatly increase the effeciency, preventing long pauses waiting for a non-collision number:

    static void Main(string[] args)
    {
        List<int> numbers = new List<int>();

        Random ran = new Random();
        int number = 0;
        int min = 1;
        int max = 51;

        for (int i = 0; i < 50; i++)
        {
            do
            {
                number = ran.Next(min, max);
            }
            while (numbers.Contains(number));

            numbers.Add(number);

            if (number == min) min++;
            if (number == max - 1) max--;
        }

        for (int i = 0; i < 50; i++)
            Console.WriteLine(numbers[i]);

        Console.ReadKey();
    }

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