“超级"问题:“错误:"(“预期") [英] "Super" issue: "error: '(' expected"

问题描述

您好，感谢阅读！

我使用for"来读取数组列表中的每个对象，并想检查为每个对象返回函数 getType() 的字符串，该字符串存在于对象的扩展类中.

I use a "for" to read every object in an arraylist, and want to check the string that returns the function getType() for each object, which exists in the extended class of the objects.

for(int i=0; i<cat.items.size(); i++)
        {
            if ( cat.items.get(i).super.getType().equals(type) );
            {

但是，我收到错误

    MainApp.java:17: error: '(' expected 
if ( cat.items.get(i).super.getType().equals(type) );
                           ^

我认为我没有正确使用超级".你能提供一个替代方案吗?

I think that I don't user "super" correctly. Can you offer an alternative?

再次感谢！

推荐答案

你能提供替代方案吗?

Can you offer an alternative?

假设getType是由类或子类实现的，那么使用方法如下:

Assuming that getType is implemented by the class or a suberclass, then this is the way to use it:

  cat.items.get(i).getType().equals(type)

请注意，如果子类覆盖了在超类中实现的 getType() 方法，则上面将调用该方法的子类版本.不能在超类¹中调用被覆盖的方法.

Note that if the subclass overrides a getType() method that is implemented in the superclass, the above will call the subclass version of the method. You can't call the overridden method in the superclass¹.

^{1 - 嗯……不是在这种情况下.覆盖方法可以调用super.getType()，但这只能对目标对象进行；即这个".它不适用于您的示例.}

^{1 - Well ... not in this case. An override method can call super.getType(), but that can only be done for the target object; i.e. "this". It doesn't apply to your example.}

这篇关于“超级"问题:“错误:"(“预期")的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！