初始化固定长度数组的正确方法是什么? [英] What is the proper way to initialize a fixed length array?
问题描述
我在初始化固定长度数组时遇到问题.到目前为止我的尝试都导致相同的使用可能未初始化的变量:foo_array
"错误:
I'm having trouble initializing a fixed length array. My attempts so far all result in the same "use of possibly uninitialized variable: foo_array
" error:
#[derive(Debug)]
struct Foo { a: u32, b: u32 }
impl Default for Foo {
fn default() -> Foo { Foo{a:1, b:2} }
}
pub fn main() {
let mut foo_array: [Foo; 10];
// Do something here to in-place initialize foo_array?
for f in foo_array.iter() {
println!("{:?}", f);
}
}
error[E0381]: use of possibly uninitialized variable: `foo_array`
--> src/main.rs:13:14
|
13 | for f in foo_array.iter() {
| ^^^^^^^^^ use of possibly uninitialized `foo_array`
我实现了 Default
trait,但 Rust 似乎并没有像 C++ 构造函数那样默认调用它.
I implemented the Default
trait, but Rust does not seem to call this by default akin to a C++ constructor.
初始化固定长度数组的正确方法是什么?我想做一个高效的就地初始化,而不是某种复制.
What is the proper way to initialize a fixed length array? I'd like to do an efficient in-place initialization rather than some sort of copy.
推荐答案
The safe but 有点低效的解决方案:
The safe but somewhat inefficient solution:
#[derive(Copy, Clone, Debug)]
struct Foo {
a: u32,
b: u32,
}
fn main() {
let mut foo_array = [Foo { a: 10, b: 10 }; 10];
}
因为您特别要求 没有副本的解决方案:
use std::mem::MaybeUninit;
#[derive(Debug)]
struct Foo {
a: u32,
b: u32,
}
// We're just implementing Drop to prove there are no unnecessary copies.
impl Drop for Foo {
fn drop(&mut self) {
println!("Destructor running for a Foo");
}
}
pub fn main() {
let array = {
// Create an array of uninitialized values.
let mut array: [MaybeUninit<Foo>; 10] = unsafe { MaybeUninit::uninit().assume_init() };
for (i, element) in array.iter_mut().enumerate() {
let foo = Foo { a: i as u32, b: 0 };
*element = MaybeUninit::new(foo);
}
unsafe { std::mem::transmute::<_, [Foo; 10]>(array) }
};
for element in array.iter() {
println!("{:?}", element);
}
}
这是由 MaybeUninit
的文档.
This is recommended by the documentation of MaybeUninit
.
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