通过搜索嵌套对象属性过滤对象数组 [英] Filtering array of objects by searching nested object properties
问题描述
我有一个对象数组,我想通过将嵌套属性与搜索词进行比较来过滤这些对象.
例如:
var 数组 = [{类别:'商业'用户: [{名称:'莎莉'标签:[{标签:'会计'},{标签:'营销'},...]},{名称:'鲍勃'标签:[{标签:'销售'},{标签:'会计'},...]} ...]},{类别:'遗产'用户: [{名称:'琳达'标签:[{标签:'意大利'},{标签:'马其顿'},...]},{名称:'乔治'标签:[{标签:'南非'},{标签:'智利'},...]},...]},...[
本质上,我想通过搜索词过滤对象的基本数组,该搜索词包括嵌套对象 2 数组中标记属性字符串中的字符.
因此搜索市场"将导致
<预><代码>[{类别:'商业'用户: [{名称:'莎莉'标签:[{标签:'会计'},{标签:'营销'},...]},{名称:'鲍勃'标签:[{标签:'销售'},{标签:'会计'},...]} ...]}]谢谢.
你可以使用 Array#filter
使用 Array#some
.
如果在嵌套数组中找到标记,则停止迭代并将结果返回给过滤器回调.
var array = [{ category: 'Business', users: [{ name: 'Sally', tags: [{ tag: 'accounting' }, { tag: 'marketing' }] }, { name: 'Bob', tags: [{ tag: 'sales' }, { tag: 'accounting' }] }] }, { category: 'Heritage',用户:[{名称:'琳达',标签:[{标签:'意大利'},{标签:'马其顿'}]},{名称:'乔治',标签:[{标签:'南非'},{ tag: '智利' }] }] }],标签 = '营销',结果 = array.filter(a => a.users.some(u => u.tags.some(t => t.tag.includes(tag))));console.log(result);
.as-console-wrapper { max-height: 100% !important;顶部:0;}
I have an array of objects that I want to filter by comparing a nested property to a search term.
For example:
var array = [
{category: 'Business'
users: [
{name: 'Sally'
tags: [{tag: 'accounting'}, {tag: 'marketing'},...]
},
{name: 'Bob'
tags: [{tag: 'sales'}, {tag: 'accounting'},...]
}...
]
},
{category: 'Heritage'
users: [
{name: 'Linda'
tags: [{tag: 'Italy'}, {tag: 'Macedonia'},...]
},
{name: 'George'
tags: [{tag: 'South Africa'}, {tag: 'Chile'},...]
},...
]
},...
[
Essentially I want to filter the base array of objects by a search terms that include characters from the tag property string in the nested objects 2 arrays down.
So a search for 'market' would result in
[
{category: 'Business'
users: [
{name: 'Sally'
tags: [{tag: 'accounting'}, {tag: 'marketing'},...]
},
{name: 'Bob'
tags: [{tag: 'sales'}, {tag: 'accounting'},...]
}...
]
}
]
Thank you.
You could use Array#filter
with looking into the nested arrays by using Array#some
.
If the tag is found in a nested array, then iteration stops and the result is given back to the filter callback.
var array = [{ category: 'Business', users: [{ name: 'Sally', tags: [{ tag: 'accounting' }, { tag: 'marketing' }] }, { name: 'Bob', tags: [{ tag: 'sales' }, { tag: 'accounting' }] }] }, { category: 'Heritage', users: [{ name: 'Linda', tags: [{ tag: 'Italy' }, { tag: 'Macedonia' }] }, { name: 'George', tags: [{ tag: 'South Africa' }, { tag: 'Chile' }] }] }],
tag = 'marketing',
result = array.filter(a => a.users.some(u => u.tags.some(t => t.tag.includes(tag))));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
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