检查数组是否为空 [英] Check whether an array is empty

问题描述

我有以下代码

<?php

$error = array();
$error['something'] = false;
$error['somethingelse'] = false;

if (!empty($error))
{
    echo 'Error';
}
else
{
    echo 'No errors';
}

?>

然而，empty($error) 仍然返回 true，即使什么都没有设置.

However, empty($error) still returns true, even though nothing is set.

哪里不对?

推荐答案

数组中有两个元素，这绝对不意味着数组为空.作为快速解决方法，您可以执行以下操作:

There are two elements in array and this definitely doesn't mean that array is empty. As a quick workaround you can do following:

$errors = array_filter($errors);

if (!empty($errors)) {
}

array_filter() 函数的默认行为将从数组中删除所有等于 null, 0, '' 或 false.

array_filter() function's default behavior will remove all values from array which are equal to null, 0, '' or false.

否则在您的特定情况下，empty() 构造将始终返回 true，如果至少有一个元素具有空"值.

Otherwise in your particular case empty() construct will always return true if there is at least one element even with "empty" value.

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