Swift 中的多维数组 [英] Multidimensional arrays in Swift
本文介绍了Swift 中的多维数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
正如 Adam Washington 所指出的,从 Beta 6 开始,此代码按原样运行,因此问题不再相关.
As Adam Washington points out, as from Beta 6, this code works as is, so the question is no longer relevant.
我正在尝试创建并遍历二维数组:
I am trying to create and iterate through a two dimensional array:
var array = Array(count:NumColumns, repeatedValue:Array(count:NumRows, repeatedValue:Double()))
array[0][0] = 1
array[1][0] = 2
array[2][0] = 3
array[0][1] = 4
array[1][1] = 5
array[2][1] = 6
array[0][2] = 7
array[1][2] = 8
array[2][2] = 9
for column in 0...2 {
for row in 0...2 {
println("column: \(column) row: \(row) value:\(array[column][row])")
}
}
然而,这是我得到的输出:
However, this is the output I get:
column: 0 row: 0 value:3.0
column: 0 row: 1 value:6.0
column: 0 row: 2 value:9.0
column: 1 row: 0 value:3.0
column: 1 row: 1 value:6.0
column: 1 row: 2 value:9.0
column: 2 row: 0 value:3.0
column: 2 row: 1 value:6.0
column: 2 row: 2 value:9.0
看起来好像行中的最后一列覆盖了其他列的值.
It looks as if the last column in the row is overwriting the other column values.
我说错了吗?
也许游乐场的图片会有所帮助:
Perhaps a picture from the Playground would help:
推荐答案
对于未来的读者,这里有一个优雅的解决方案 (5x5):
For future readers, here is an elegant solution(5x5):
var matrix = [[Int]](repeating: [Int](repeating: 0, count: 5), count: 5)
和动态方法:
var matrix = [[Int]]() // creates an empty matrix
var row = [Int]() // fill this row
matrix.append(row) // add this row
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