从数组中删除匹配元素的第一个实例 [英] Delete first instance of matching element from array

问题描述

假设我有数组 [1,2,3,1,2,3] 并且我想从数组给出 [1,3,1,2,3].最简单的方法是什么?

Say I have the array [1,2,3,1,2,3] and I want to delete the first instance of (say) 2 from the array giving [1,3,1,2,3]. What's the easiest way?

推荐答案

li.delete_at(li.index(n) || li.length)

li[li.length] 超出范围，所以 ||li.length 处理 n 不在列表中的情况.

li[li.length] is out of range, so the || li.length handles the case where n isn't in the list.

irb(main):001:0> li = [1,2,3,1,2,3]
=> [1, 2, 3, 1, 2, 3]
irb(main):002:0> li.delete_at(li.index(2) || li.length)
=> 2
irb(main):003:0> li.delete_at(li.index(42) || li.length)
=> nil
irb(main):004:0> li
=> [1, 3, 1, 2, 3]

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