bash 脚本，创建目录中所有文件的数组 [英] bash script, create array of all files in a directory

问题描述

我有一个包含许多 .html 文件的目录 myDir.我正在尝试创建目录中所有文件的数组，以便我可以索引该数组并能够引用目录中的特定 html 文件.我尝试了以下行:

I have a directory myDir of many .html files. I am trying to create an array of all the files in the directory so I might be able to index the array and be able to refer to particular html files in the directory. I have tried the following line:

myFileNames=$(ls ~/myDir)

for file in $myFileNames; 
#do something

但我希望能够拥有一个计数器变量并具有如下逻辑:

but I want to be able to have a counter variable and have logic like the following:

 while $counter>=0;
   #do something to myFileNames[counter]

我对 shell 脚本很陌生，无法弄清楚如何实现这一点，因此希望得到有关此问题的任何帮助.

I am quite new to shell scripting and am unable to figure out how to achieve this hence would appreciate any help regarding this matter.

推荐答案

您可以:

# use nullglob in case there are no matching files
shopt -s nullglob

# create an array with all the filer/dir inside ~/myDir
arr=(~/myDir/*)

# iterate through array using a counter
for ((i=0; i<${#arr[@]}; i++)); do
    #do something to each element of array
    echo "${arr[$i]}"
done

您也可以为数组的迭代执行此操作:

You can also do this for iteration of array:

for f in "${arr[@]}"; do
   echo "$f"
done

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