检查两个numpy数组python中有多少元素相等 [英] check how many elements are equal in two numpy arrays python

问题描述

我有两个带有数字(相同长度)的 numpy 数组，我想计算这两个数组之间有多少个元素相等(相等 = 数组中相同的值和位置)

A = [1, 2, 3, 4]B = [1, 2, 4, 3]

然后我希望返回值为 2(只有 1&2 的位置和值相等)

解决方案

使用 numpy.sum:

<预><代码>>>>将 numpy 导入为 np>>>a = np.array([1, 2, 3, 4])>>>b = np.array([1, 2, 4, 3])>>>np.sum(a == b)2>>>(a == b).sum()2

I have two numpy arrays with number (Same length), and I want to count how many elements are equal between those two array (equal = same value and position in array)

A = [1, 2, 3, 4]
B = [1, 2, 4, 3]

then I want the return value to be 2 (just 1&2 are equal in position and value)

解决方案

Using numpy.sum:

>>> import numpy as np
>>> a = np.array([1, 2, 3, 4])
>>> b = np.array([1, 2, 4, 3])
>>> np.sum(a == b)
2
>>> (a == b).sum()
2

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