从数组中删除重复的元素 [英] Remove from the array elements that are repeated

问题描述

从数组中删除重复元素的最佳方法是什么.例如，从数组

What is the best way to remove from the array elements that are repeated. For example, from the array

a = [4, 3, 3, 1, 6, 6]

需要得到

a = [4, 1]

我的方法在处理大量元素时工作速度太慢.

My method works to too slowly with big amount of elements.

arr = [4, 3, 3, 1, 6, 6]
puts arr.join(" ")
nouniq = []
l = arr.length
uniq = nil
for i in 0..(l-1)
  for j in 0..(l-1) 
    if (arr[j] == arr[i]) and ( i != j )
      nouniq << arr[j]
    end
  end
end
arr = (arr - nouniq).compact

puts arr.join(" ")

推荐答案

a = [4, 3, 3, 1, 6, 6]
a.select{|b| a.count(b) == 1}
#=> [4, 1]

更复杂但更快的解决方案 (O(n) 我相信 :))

More complicated but faster solution (O(n) I believe :))

a = [4, 3, 3, 1, 6, 6]
ar = []
add = proc{|to, form| to << from[1] if form.uniq.size == from.size }
a.sort!.each_cons(3){|b| add.call(ar, b)}
ar << a[0] if a[0] != a[1]; ar << a[-1] if a[-1] != a[-2]

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