为什么不可能在 C++ 中创建一个引用数组? [英] Why it is impossible to create an array of references in c++?

问题描述

C++ 标准 8.3.2/4 说:

C++ Standard 8.3.2/4 says:

不得引用引用，没有引用数组，并且没有指向引用的指针.

There shall be no references to references, no arrays of references, and no pointers to references.

但我不明白为什么将这个限制添加到 C++ 中.在我看来，下面的代码可以很容易地编译和工作?这种限制的真正原因是什么?

But I can't understand why this restriction is added to c++. In my opinion the code bellow can easily be compiled and work? What is the real cause of this restriction?

int a = 10, b = 20;
int &c[] = {a, b};

推荐答案

因为数组的索引实际上是根据隐式转换为指针定义的，然后是指针运算.因此，要支持这一点，您还必须支持指向引用的指针，并定义指针算术对它们的含义.

Because indexation into an array is actually defined in terms of an implicit conversion to a pointer, then pointer arithmetic. So to support this, you'd have to also support pointers to references, and define what pointer arithmetic means on them.

这篇关于为什么不可能在 C++ 中创建一个引用数组?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！