在 numpy 中获取 3D 数组的 2D 切片的平均值 [英] Get mean of 2D slice of a 3D array in numpy
问题描述
我有一个形状为的 numpy 数组:
(11L, 5L, 5L)
我想计算数组 [0, :, :], [1, :, :] 等的每个切片"的 25 个元素的平均值,返回 11 个值.
这看起来很傻,但我不知道如何做到这一点.我认为 mean(axis=x)
函数可以做到这一点,但我已经尝试了所有可能的轴组合,但没有一个给我想要的结果.
我显然可以使用 for 循环和切片来做到这一点,但肯定有更好的方法吗?
对轴使用元组:
<预><代码>>>>a = np.arange(11*5*5).reshape(11,5,5)>>>a.mean(axis=(1,2))数组([ 12., 37., 62., 87., 112., 137., 162., 187., 212.,237., 262.])这仅适用于 numpy 1.7+ 版.
I have a numpy array with a shape of:
(11L, 5L, 5L)
I want to calculate the mean over the 25 elements of each 'slice' of the array [0, :, :], [1, :, :] etc, returning 11 values.
It seems silly, but I can't work out how to do this. I've thought the mean(axis=x)
function would do this, but I've tried all possible combinations of axis and none of them give me the result I want.
I can obviously do this using a for loop and slicing, but surely there is a better way?
Use a tuple for axis :
>>> a = np.arange(11*5*5).reshape(11,5,5)
>>> a.mean(axis=(1,2))
array([ 12., 37., 62., 87., 112., 137., 162., 187., 212.,
237., 262.])
Edit: This works only with numpy version 1.7+.
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