如何仅在jquery中的2个数组之间找到公共元素 [英] How to find common elements only between 2 arrays in jquery

问题描述

var array1 = [1, 2, 3, 4, 5, 6];
var array2 = [1, 2, 3, 4, 5, 6, 7, 8, 9];

我有两个像上面一样的数组.现在我想使用 jQuery 在 MVC 4 中执行以下操作.

I have two arrays like above. Now I want to do the following in MVC 4 with jQuery.

1. 如果两个数组的每个元素都相等，则显示消息/警报.例如所有记录已经存在."

1. If every elements of both arrays are equal then show a message/alert. e.g. "All records already existing."

如果两个数组的每个元素都不同，则只需将它们全部添加到VAR"中，例如var resultset = ....(其中 7,8,9 将存储)

If every elements of both the arrays are different then just add them all in a "VAR", e.g. var resultset = .... (where 7,8,9 will stored)

如果两个数组之间的公共元素很少，那么对于公共元素，会显示带有元素的消息，例如记录 1、2、3、4、5、6 已经存在"并在VAR"中添加不同的元素，例如var resultset = .... (其中 7,8,9 将存储).消息和差异元素集合将同时执行.

If few elements common between two arrays then for the common elements show a message with element, e.g. "Record 1,2,3,4,5,6 are already exists" and add the different elements in "VAR", e.g. var resultset = .... (where 7,8,9 will stored). Both the message and difference elements collection will perform at the same time.

推荐答案

试试这个:

    var array1  = [1, 2, 3, 4, 5, 6],
    array2 = [1, 2, 3, 4, 5, 6, 7, 8, 9];

var common = $.grep(array1, function(element) {
    return $.inArray(element, array2 ) !== -1;
});

console.log(common); // returns [1, 2, 3, 4, 5, 6];



var array3 = array2.filter(function(obj) { return array1.indexOf(obj) == -1; });

// returns [7,8,9];

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