使用另一个 MySQL 表的值更新一个 MySQL 表 [英] Update one MySQL table with values from another

查看:64
本文介绍了使用另一个 MySQL 表的值更新一个 MySQL 表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试根据另一个 MySQL 表的信息更新一个 MySQL 表.

I'm trying to update one MySQL table based on information from another.

我的原始表看起来像:

id | value
------------
1  | hello
2  | fortune
3  | my
4  | old
5  | friend

tobeupdated 表看起来像:

uniqueid | id | value
---------------------
1        |    | something
2        |    | anything
3        |    | old
4        |    | friend
5        |    | fortune

我想根据 value<用 original 中的 id 更新 tobeupdated 中的 id/code>(存储在 VARCHAR(32) 字段中的字符串).

I want to update id in tobeupdated with the id from original based on value (strings stored in VARCHAR(32) field).

更新后的表格有望如下所示:

The updated table will hopefully look like:

uniqueid | id | value
---------------------
1        |    | something
2        |    | anything
3        | 4  | old
4        | 5  | friend
5        | 2  | fortune

我有一个有效的查询,但速度很慢:

I have a query that works, but it's very slow:

UPDATE tobeupdated, original
SET tobeupdated.id = original.id
WHERE tobeupdated.value = original.value

这会最大化我的 CPU 并最终导致只执行一小部分更新的超时(有几千个值要匹配).我知道按 value 匹配会很慢,但这是我必须将它们匹配在一起的唯一数据.

This maxes out my CPU and eventually leads to a timeout with only a fraction of the updates performed (there are several thousand values to match). I know matching by value will be slow, but this is the only data I have to match them together.

有没有更好的方法来更新这样的值?我可以为合并的结果创建第三个表,如果那样会更快?

Is there a better way to update values like this? I could create a third table for the merged results, if that would be faster?

我尝试了 MySQL - 如何我可以用另一个表中的值更新一个表吗?,但这并没有真正的帮助.有什么想法吗?

I tried MySQL - How can I update a table with values from another table?, but it didn't really help. Any ideas?

预先感谢您帮助 MySQL 新手!

Thanks in advance for helping a MySQL novice!

推荐答案

UPDATE tobeupdated
INNER JOIN original ON (tobeupdated.value = original.value)
SET tobeupdated.id = original.id

那应该可以,而且它确实在做你的事情.但是,我更喜欢连接的JOIN"语法而不是多个WHERE"条件,我认为它更容易阅读

That should do it, and really its doing exactly what yours is. However, I prefer 'JOIN' syntax for joins rather than multiple 'WHERE' conditions, I think its easier to read

至于运行缓慢,表有多大?您应该在 tobeupdated.valueoriginal.value

As for running slow, how large are the tables? You should have indexes on tobeupdated.value and original.value

我们也可以简化查询

UPDATE tobeupdated
INNER JOIN original USING (value)
SET tobeupdated.id = original.id

USING 是当连接的两个表具有相同的名称 key(例如 id)时的简写.即 equi-join - http://en.wikipedia.org/wiki/Join_(SQL)#Equi-join

USING is shorthand when both tables of a join have an identical named key such as id. ie an equi-join - http://en.wikipedia.org/wiki/Join_(SQL)#Equi-join

这篇关于使用另一个 MySQL 表的值更新一个 MySQL 表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆