检查查询结果是否为空行 mysqli [英] check if the query results empty row mysqli
本文介绍了检查查询结果是否为空行 mysqli的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用此代码,但我不明白如何检查查询是否返回零行.我该如何检查?
I am using this code, but I don't understand how to check if the query returns zero rows. How can I check that?
$results = $mysqli->query("SELECT ANNOUNCE_NUMBER,ANNOUNCEMENTS,ANNOUNCE_TYPE,POST_DATE FROM home WHERE ANNOUNCE_NUMBER NOT LIKE $excludewelcome AND ANNOUNCE_NUMBER NOT LIKE $excludenews ORDER BY ANNOUNCE_NUMBER DESC LIMIT $position, $items_per_group");
if ($results) {
//output results from database
while($obj = $results->fetch_object())
{
if($obj->ANNOUNCE_TYPE=='NEWSEVENTS')
{
$realstring='News and Events';
}
else
{
$realstring='Welcome Note';
}
echo '<li id="item_'.$obj->ANNOUNCE_NUMBER.'"><strong>'.$realstring.'</strong></span>';
echo '<br \>';
echo '('.$obj->POST_DATE.' ) <span class="page_message">'.$obj->ANNOUNCEMENTS.'</span></li>';
}
}
推荐答案
您可以使用num_rows
在数据集上检查返回的行数.示例:
You can use the num_rows
on the dataset to check the number of rows returned. Example:
$results = $mysqli->query("SELECT ANNOUNCE_NUMBER,ANNOUNCEMENTS,ANNOUNCE_TYPE,POST_DATE FROM home WHERE ANNOUNCE_NUMBER NOT LIKE $excludewelcome AND ANNOUNCE_NUMBER NOT LIKE $excludenews ORDER BY ANNOUNCE_NUMBER DESC LIMIT $position, $items_per_group");
if ($results) {
if($results->num_rows === 0)
{
echo 'No results';
}
else
{
//output results from database
while($obj = $results->fetch_object())
{
if($obj->ANNOUNCE_TYPE=='NEWSEVENTS')
{
$realstring='News and Events';
}
else
{
$realstring='Welcome Note';
}
echo '<li id="item_'.$obj->ANNOUNCE_NUMBER.'"><strong>'.$realstring.'</strong></span>';
echo '<br \>';
echo '('.$obj->POST_DATE.' ) <span class="page_message">'.$obj->ANNOUNCEMENTS.'</span></li>';
}
}
}
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