Java 2D 碰撞? [英] Java 2D Collision?

问题描述

大家好，我正在制作一个 2D Java 游戏，我正在尝试弄清楚如何制作一个好的碰撞代码.我目前正在使用以下代码:

Hey guys i'm making a 2D java game and i'm trying to figure out how to make a good collision code. I am currently using the following code:

    public void checkCollision() {
    Rectangle player_rectangle = new Rectangle(player.getX(),player.getY(),32,32);

    for(Wall wall : walls) {

        Rectangle wall_rectangle = new Rectangle(wall.getX(), wall.getY(), 32,32);

        if (player_rectangle.intersects(wall_rectangle)) {
            Rectangle intersection = (Rectangle) player_rectangle.createIntersection(wall_rectangle);

            if (player.xspeed > 0) {
                player.x -= intersection.getWidth();
            }

            if (player.yspeed > 0) {
                player.y -= intersection.getHeight();
            }

            if (player.xspeed < 0) {
                player.x += intersection.getWidth();
            }

            if (player.yspeed < 0) {
                player.y += intersection.getHeight(); 
            }

            Print(Integer.toString(intersection.width) + ", " + Integer.toString(intersection.height));

        }

    }

}

使用此代码，如果您按下一个按钮，它就可以正常工作，但是如果按下并向左按下，例如玩家将向某个随机方向飞去.

With this code it works fine if you are press one button but if press down and left for example the player will fly off in some random direction.

这是我拥有的地图类型的图片:

Here is a picture of the types of maps I have:

推荐答案

你的主要问题是假设玩家直接撞到墙上.考虑有一个墙壁矩形 (100,100,32,32) 并且玩家位于 (80,68,32,32) 的情况.玩家正在向下和向左移动，因此 player.xspeed <;0 和 player.yspeed > 0;假设玩家的下一个位置是 (79,69,32,32).交点是 (100,100,11,1).

Your main problem is in assuming that the player is running directly into the wall. Consider the case where there is a wall rect (100,100,32,32) and the player is at (80,68,32,32). The player is moving down and to the left, so player.xspeed < 0 and player.yspeed > 0; say the next position for the player is (79,69,32,32). The intersection is then (100,100,11,1).

请注意，尽管玩家向左(以及向下)移动，但墙实际上位于玩家的右侧.这一行:

Note that although the player is moving left (as well as down) the wall is actually to the right of the player. This line:

if (player.xspeed < 0) {
    player.x += intersection.getWidth();
}

... 导致 player.x 突然跳转到 90.

... causes player.x to be set to 90 in a sudden jump.

您可以做的一件事是检查玩家的左侧是否包含在交叉点中，即

One thing you could do is check that the player's left-hand side was contained in the intersection, i.e.

if (player.xspeed < 0 && player.x >= intersection.x) {
    player.x += intersection.getWidth();
}

显然其他方向也需要做类似的事情.

Obviously a similar thing needs to be done for the other directions too.

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