将 32 位实数转换为 2x 16 位字节 [英] Converting 32-Bit Real to 2x 16-Bit Bytes
问题描述
我正在尝试通过 CAN 通信 (IFM) 发送 32 位实数,但 CAN 通信仅接受 16 位值.
I'm trying to send a 32-Bit Real across a CAN communications (IFM) but the CAN comms only accepts a 16-Bit value.
如果我尝试发送的值超过 255,它会重置为 0 并以该模式继续.因此,我需要将 32 位 Real 值拆分为两个 16 位值,然后在通信的另一侧重新组装.
If the value I'm trying to send goes above 255, it resets back to 0 and continues in that pattern. I therefore need to split the 32-Bit Real value in to two 16-Bit values and then reassemble on the other side of the comms.
我似乎无法理解如何在结构化文本中进行操作.
I just can't seem to get my head around how to do it in structured text.
任何帮助将不胜感激
推荐答案
我知道我参加聚会有点晚了,但想将其添加为解决方案.
I know I am a little late to the party but wanted to add this as a solution.
VAR
rRealVar : REAL;
awWordArray : ARRAY[0..1] OF WORD;
pTemp : POINTER TO REAL;
pTemp2 : POINTER TO REAL;
END_VAR
// Get a pointer to the REAL variable
pTemp := ADR(rRealVar);
// Get a pointer to the ARRAY base
pTemp2 := ADR(awWordArray);
// Assign the value of the REAL variable into the ARRAY base
pTemp2^ := pTemp^;
(* Index 0 := Bits 15-0
Index 1 := Bits 31-16
这类似于 Felix Keil 的回答,但它使用 2 个 pointer
变量和一个 word array
来直接检索信息.
This is similar to Felix Keil's answer but it makes use of 2 pointer
variables and a word array
to retrieve the information directly.
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