获取正则表达式匹配后的文本 [英] Getting the text that follows after the regex match

问题描述

我是使用 Regex 的新手，我已经阅读了一系列教程，但我还没有找到适合我想做的事情的教程，

I'm new to using Regex, I've been going through a rake of tutorials but I haven't found one that applies to what I want to do,

我想搜索一些东西，但返回它后面的所有内容，而不是搜索字符串本身

I want to search for something, but return everything following it but not the search string itself

例如一些蹩脚的句子，很棒"

搜索句子"

返回太棒了"

任何帮助将不胜感激

这是我目前的正则表达式

This is my regex so far

sentence(.*) 

但它返回:这句真棒

Pattern pattern = Pattern.compile("sentence(.*)");

Matcher matcher = pattern.matcher("some lame sentence that is awesome");

boolean found = false;
while (matcher.find())
{
    System.out.println("I found the text: " + matcher.group().toString());
    found = true;
}
if (!found)
{
    System.out.println("I didn't find the text");
}

推荐答案

您可以按照您在评论中的要求使用仅使用正则表达式":

You can do this with "just the regular expression" as you asked for in a comment:

(?<=sentence).*

(?<=sentence) 是一个积极的后视断言.这会在字符串中的某个位置匹配，即在文本 sentence 之后的位置，而不会使该文本本身成为匹配的一部分.因此，(?<=sentence).* 将匹配 sentence 之后的任何文本.

(?<=sentence) is a positive lookbehind assertion. This matches at a certain position in the string, namely at a position right after the text sentence without making that text itself part of the match. Consequently, (?<=sentence).* will match any text after sentence.

这是正则表达式的一个很好的特性.但是，在 Java 中，这仅适用于有限长度的子表达式，即.e.(?<=sentence|word|(foo){1,4}) 是合法的，但 (?<=sentences*) 不是.

This is quite a nice feature of regex. However, in Java this will only work for finite-length subexpressions, i. e. (?<=sentence|word|(foo){1,4}) is legal, but (?<=sentences*) isn't.

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