从类路径资源(XML 文件)获取输入流 [英] Getting the inputstream from a classpath resource (XML file)
问题描述
在Java web应用程序中,假设我想获取一个XML文件的InputStream,该文件位于CLASSPATH(即sources文件夹内),我该怎么做?>
In Java web application, Suppose if I want to get the InputStream of an XML file, which is placed in the CLASSPATH (i.e. inside the sources folder), how do I do it?
推荐答案
ClassLoader.getResourceAsStream()
.
正如下面的评论中所述,如果您处于多ClassLoader
环境(例如单元测试、webapps 等)中,您可能需要使用 Thread.currentThread().getContextClassLoader()
.请参阅http://stackoverflow.com/questions/2308188/getresourceasstream-vs-fileinputstream/230838837307593_21307593_2308182.
As stated in the comment below, if you are in a multi-ClassLoader
environment (such as unit testing, webapps, etc.) you may need to use Thread.currentThread().getContextClassLoader()
. See http://stackoverflow.com/questions/2308188/getresourceasstream-vs-fileinputstream/2308388#comment21307593_2308388.
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