等待具有不同结果的多个任务 [英] Awaiting multiple Tasks with different results
问题描述
我有 3 个任务:
private async Task<Cat> FeedCat() {}
private async Task<House> SellHouse() {}
private async Task<Tesla> BuyCar() {}
在我的代码可以继续之前,它们都需要运行,我也需要每个的结果.结果没有任何共同点
They all need to run before my code can continue and I need the results from each as well. None of the results have anything in common with each other
如何调用并等待 3 个任务完成然后获取结果?
How do I call and await for the 3 tasks to complete and then get the results?
推荐答案
使用 WhenAll
后,可以使用 await
单独拉出结果:
After you use WhenAll
, you can pull the results out individually with await
:
var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();
await Task.WhenAll(catTask, houseTask, carTask);
var cat = await catTask;
var house = await houseTask;
var car = await carTask;
您也可以使用 Task.Result
(因为您知道此时它们都已成功完成).但是,我建议使用 await
因为它显然是正确的,而 Result
在其他情况下可能会导致问题.
You can also use Task.Result
(since you know by this point they have all completed successfully). However, I recommend using await
because it's clearly correct, while Result
can cause problems in other scenarios.
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