jquery 多级手风琴 [英] jquery multi level accordion

问题描述

我有一个简单的多级手风琴插件.这对我来说几乎是完美的.

I've got simple multi level accordion plugin. It's almost perfect for me.

(function(jQuery){
     jQuery.fn.extend({  
         accordion: function() {       
            return this.each(function() {

                var $ul = $(this);

                if($ul.data('accordiated'))
                    return false;

                $.each($ul.find('ul, li>div'), function(){
                    $(this).data('accordiated', true);
                    $(this).hide();
                });

                $.each($ul.find('a'), function(){
                    $(this).click(function(e){
                        activate(this);
                        return void(0);
                    });
                });

                var active = $('.active');

                if(active){
                    activate(active, 'toggle');
                    $(active).parents().show();
                }

                function activate(el,effect){
                    $(el).parent('li').toggleClass('active').siblings().removeClass('active').children('ul, div').slideUp('fast');
                    $(el).siblings('ul, div')[(effect || 'slideToggle')]((!effect)?'fast':null);
                }

            });
        } 
    }); 
})(jQuery);

完整代码 - http://jsfiddle.net/SKfax/

我正在尝试稍微重新编写此代码，但没有成功.我只需要在 'a' 元素中切换 Class('.active') 和 removeClass('.active') 而不是它们的父元素 'li'

I'm trying to slightly remake this code, but without any success. I need to toggleClass('.active') and removeClass('.active') only inside 'a' elements and not their parent 'li'

P.S.:'.active' 类仅适用于当前打开的部分的标题.

P.S.: '.active' class applies only to the headings of currently opened sections.

推荐答案

这是一个适当的逻辑难题，但我想我已经解决了(如果我有误解，请告诉我):

This was a proper logical conundrum, but I think I have got it working (let me know if I have misunderstood):

JSFiddle

我认为关键是防止 activate 函数中的第一个链在第一次通过时运行.所以当你在这里调用 activate 时:

I think the key was to prevent the first chain in the activate function from running on the first pass. So when you call activate here:

var active = $('.active');

if(active){
    activate(active, 'toggle');
    $(active).parents().show();
}

...您不想执行向上滑动兄弟并切换 active 类的链.

...you don't want to execute the chain that slides up siblings and toggles the active class.

我还调整了 activate 功能，如下所述:

I have also tweaked the activate function as described below:

function activate(el,effect){

    //only do this if no effect is specified (i.e. don't do this on the first pass)
    if (!effect) {
        $(el)
             .toggleClass('active') //first toggle the class of the clicked element (i.e. the 'a' tag)
             .parent('li') //now we go up the DOM to the parent 'li'
             .siblings() //get the sibling li's
             .find('a') //get the 'a' tags below them (assuming there are no 'a' tags in the content text!)
             .removeClass('active') //remove active class from these 'a' tags
             .parent('li')
             .children('ul, div')
             .slideUp('fast'); //and hide the sibling content
    }

    //I haven't touched this
    $(el).siblings('ul, div')[(effect || 'slideToggle')]((!effect)?'fast':null);
}

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